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3 years ago

Find the number of moles of argon in 452 g of argon

Chemistry

2 answers:

bixtya [17]3 years ago

7 0

No. of moles = given mass/atomic mass

= 452/40

= 11.3.

Thus, there are 11.3 moles

Law Incorporation [45]3 years ago

3 0

Nó of moles =given mass/molar mass
no of moles=452/39.9
therefore no of moles=11.3moles

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What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te

Ierofanga [76]

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

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2 years ago

How to differentiate between so3 and so4?

makvit [3.9K]

Answer:

The difference between sulfate and sulfite is, Sulfate (SO4) has 1 atom of Sulphur and 4 atoms of Oxygen. sulfite (SO3) has 1 atom of sulfur and 3 atoms of Oxygen.

Explanation:

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2 years ago

Order the density of the layers of the Earth from lowest density to highest

tatiyna

Answer:

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3 years ago

OxYgen and hydrogen particles are kept in a container. Which of the following

Tema [17]

Answer:

Option D

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Explanation:

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3 years ago

Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.4 ∘C. A 250 mL sealed flask contains

erastova [34]

Given that:

The heat of vaporization = 22.44 kJ/mol = 22440 J/mol
normal boiling point which is the initial temperature = 0.4° C = (273 + (-0.4))K = 272.6 K
volume = 250 mL = 0.250 L
Mass of butane = 0.8 g
the final temperature = -22° C = (273 + (-22)) K = 251 K

The first step is to determine the vapor pressure at the final temperature of 251K by using the Clausius-Clapeyron equation. This is following by using the ideal gas equation to determine the numbers of moles of butane gas. After that, the mass of butane present in the liquid is determined by using the relation for the number of moles.

Using Clausius-Clapeyron Equation:

$\mathbf{In (\dfrac{P_2}{P_1} )= -\dfrac{\Delta H_{vap}}{R}(\dfrac{1}{T_2} - \dfrac{1}{T_1})}$