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Shkiper50 [21]
4 years ago
9

Which of these statements are true? Select all that apply.

Chemistry
2 answers:
Anarel [89]4 years ago
4 0
In order to find the two statements, we must first define what the enthalpy of formation and the enthalpy of reaction mean.

Enthalpy of formation:
The change in enthalpy when one mole of substance is formed from its constituent elemetns at standard state.

Enthalpy of reaction:
The change in enthalpy when a reaction occurs and the reactants and products are in their standard states.

Now, we check the statements. The true ones are:

The Hrxn for C(s) + O₂(g) → CO₂(g) is the same as Hf for CO₂
This is true because the formation of carbon dioxide requires carbon and oxygen in their standard states.

T
he Hf for Br₂<span>(l) is 0 kJ/mol by definition.
Because the bromine is present in its standard state, the enthalpy of formation is 0.

</span><span>The Hrxn for the reaction 1.5H</span>₂<span>(g) + 0.5N</span>₂<span>(g) </span>→ <span>NH</span>₃<span>(g) is the same as the Hf for NH</span>₃<span>(g)
The reactants and products are present in their standard state, and the reaction is the same as the one occurring during the formation of ammonia.
</span>
morpeh [17]4 years ago
3 0

Answer:

1,3,6

Explanation:

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Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na
Vedmedyk [2.9K]

Answer:

pH=13

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

HA\rightleftharpoons H^+ + A^-

Which occurs in aqueous phase, therefore, the law of mass action is written by:

Ka=\frac{[H^+][A^-]}{[HA]}

That in terms of the change x due to the reaction's extent we can write:

1x10^{-20}=\frac{x*x}{0.1M-x}

But we prefer to compute the Kb due to its exceptional weakness:

Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}}  =1x10^{-6}

Next, the acid dissociation in the presence of the base we have:

Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}

Whose solution is x=0.0999M which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

pOH=-log([OH^-])=-log(0.0999)=1

Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:

pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13

Regards.

5 0
4 years ago
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The gold-foil experiment was used to discover which subatomic particle? Question 2 options: electrons protons ==&gt; neutrons (m
Gelneren [198K]
Proton, the gold foil experiment indicated that the nucleus has a positive charge.
8 0
3 years ago
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allochka39001 [22]

Answer:

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4 0
3 years ago
1. If a person's mass is 56 kg, what is this weight in pounds?<br> 56kg
Natali [406]

Answer:

123lb

Explanation:

lb= 2.2046 kg

56×2.2046= 123lb

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3 years ago
What is the pH of 15 mL of .2 M HCl
fenix001 [56]
Easy peasy! All we need to do is plug this formula into our calculator:

-log(M)

So, we'd plug in -log(.2), which is 0.7 :)
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4 years ago
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