It is a solid substance that has a conductivity between that of an insulator and that of most metals, either due to the addition of an impurity or because of temperature effects
The range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x 
90° 0
180° - 375 π x 
We have current carrying wire in a form of a circle placed in a uniform magnetic field.
We have to the range of potential energies of the wire-field system for different orientations of the circle.
<h3>What is the formula to calculate the Magnetic Potential Energy?</h3>
The formula to calculate the magnetic potential energy is -
U = M.B = MB cos 
where -
M is the Dipole Moment.
B is the Magnetic Field Intensity.
According to the question, we have -
U = M.B = MB cos 
We can write M = IA (I is current and A is cross sectional Area)
U = IAB cos 
U = Iπ
B cos 
For
= 0° →
U(Max) = MB cos(0) = MB = Iπ
B = 5 × π ×
× 3 ×
=
375 π x
.
For
= 90° →
U = MB cos (90) = 0
For
= 180° →
U(Min) = MB cos(0) = - MB = - Iπ
B = - 5 × π ×
× 3 ×
=
- 375 π x
.
Hence, the range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x 
90° 0
180° - 375 π x 
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<h2>
Answer:</h2>
<em>Hello, </em>
<h3><u>
QUESTION)</u></h3>
<em>✔ We have: KE = PE (potential energy) </em>
<em>PE = m x g x h </em>
The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2
PE1 = PE2 ⇔ PE1/PE2 = 1

The mass m1 is therefore 4 times greater than that of the stone of mass m2.