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1 year ago

What could you do to increase the electrical force between two charged particles by a factor of 16

1 answer:

4 0

Increasing one charged particle by 16 will lead to increasing the electrical force between two charged particles by a factor of 16.

<h3>What is Electrical force?</h3>

This is referred the attractive or repulsive interaction between any two charged bodies present.

F= kq1q2/r²

F1/F2= kq1q2/r² / 16kq1q2/r²

F1/F2 = 1/16

F2 = 16F1

This is therefore how to increase the electrical force between two charged particles by a factor of 16.

Read more about Electrical force here brainly.com/question/1498868

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During the formation of an ionic compound, the element with the higher ionization energy will gain electrons.

Lesechka [4]

False because you have to take it out and do it right

8 0

3 years ago

What is the formula mass for sodium chloride?

Zigmanuir [339]

Atomic mass of sodium is 22.9 g/mol
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3 0

3 years ago

Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea

galina1969 [7]

Answer:

Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)

Oxidized: Cd

Reduced: Ag

Explanation:

Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)

Cd → Cd²⁺ + 2e⁻ Half reaction oxidation

1e⁻ + Ag⁺ → Ag Half reaction reduction

Ag changed oxidation number from +1 to 0

Cd changed oxidation number from 0 to +2

Let's ballance the electrons

( Cd → Cd²⁺ + 2e⁻ ) .1

( 1e⁻ + Ag⁺ → Ag ) .2

Cd + 2e⁻ + 2Ag⁺ → 2Ag + Cd²⁺ + 2e⁻

Finally the ballance equation is:

Cd(s) + 2AgNO₃(aq) → Cd(NO₃)₂ (aq) + 2Ag(s)

4 0

3 years ago

An amphoteric salt is one that contains an anion that can act as either an acid or a base in water. Baking soda, NaHCO3, is an e

LenKa [72]

Answer:

pH = 8.34

Explanation:

The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:

H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>

<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>

Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:

pKa1 = 6.37; pKa2 = 10.32

As the pH of amphoteric salts is:

pH = (pKa1 + pKa2) / 2

3 0

3 years ago

Find the mass in grams of 3.00 x 1023 molecules of F2

LUCKY_DIMON [66]

<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})$
Multiply: $\displaystyle 18.9306 \ g \ F_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

8 0

3 years ago