Answer:
The the magnitude of the maximum velocity and acceleration are 16.93 m/s and .
Explanation:
Given that,
Rate = 2940 rev/min
Amplitude = ±5.50 cm
(a). We need to calculate the magnitude of the maximum velocity
Using formula of maximum velocity
Where, A = amplitude
Put the value into the formula
(b). We need to calculate the maximum acceleration
Using formula of maximum acceleration
Hence, The the magnitude of the maximum velocity and acceleration are 16.93 m/s and .
Complete question is: While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 60-kg person develops a power of 70 W during a race, how fast is the person running? (Assume a running step is 1.5 m long).
Answer: The person running at a speed of 2.91 m/s.
Explanation:
Given: Mass of runner = 60 kg
Runner dissipates = 0.6 J/kg per step
Average power = 70 W
1 step = 1.50 m
Energy dissipated by the runner is as follows.
Formula used to calculate the value of one step 'S' is as follows.
It is known that average velocity is equal to the total distance divided by time interval.
So, total distance for the given situation is as follows.
Hence, speed of the person is calculated as follows.
Thus, we can conclude that the person running at a speed of 2.91 m/s.
Well, just for fun, let's see hat the form of the limit is
<span>v = dx/dt = b + 3 c t^2 </span>
<span>= 1.5 + 1.92 t^2 </span>
<span>========================= </span>
<span>now </span>
<span>from 1 to 3 </span>
<span>x(3)= 1.5*3 +.64*27=4.5+17.28 </span>
<span>= 21.78 </span>
<span>x(1) = 1.5+.64 = 2.14 </span>
<span>so </span>
<span>x(3)-x(1) = 19.64 </span>
<span>delta t = 3 - 1 = 2 seconds </span>
<span>so </span>
<span>v during interval = 19.64/2 </span>
<span>= 9.82 m/s </span>
<span>now check that with calculus v in the middle of that range </span>
<span>v(2) =1.5+ 1.92 (4) = 9.18 m/s </span>
<span>that makes sense, the parabola is headed up so the instant speed i the middle should be a bit less than average. </span>
A) <span>Ivan does work when he lifts the basket
B) Work = Force * displacement
W = 20 * 2
W = 40 Joules
So, The Amount of work he does is 40 Joules
Hope this helps!</span>