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goldenfox [79]
2 years ago
5

Which statement best explains the importance of nerve cells?

Chemistry
2 answers:
faltersainse [42]2 years ago
7 0

first one, nerve cells are used to send messages from different parts of the body to the brain.

Free_Kalibri [48]2 years ago
6 0
Nerve cells re used to send messages from different parts of the body to the brain
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A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?
Licemer1 [7]

Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles

Now we have to calculate the moles of Br_2

{\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles

{\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles

The balanced chemical reaction is,

2Na(s)+Br_2(g)\rightarrow 2NaBr

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = \frac{2}{1}\times 0.189=0.378 moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

As, 1 mole of bromine give = 2 moles of Sodium bromide

So, 0.189 moles of bromine give = \frac{2}{1}\times 0.189=0.378 moles of Sodium bromide

Now we have to calculate the percent yield of reaction

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%

Therefore, the percent yield is, 93.4%

3 0
3 years ago
Who was the first to state the concept of an atom
marin [14]
Democritus, a Greek philosopher, first developed the idea of atoms (around 460 B.C., I believe).
Hope this helps!
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Find the number of moles in 3.62 x 1024 atoms of helium.
Makovka662 [10]
3.62x10^24/ 6.02x10^23=  6.013 moles to 3dp
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Would you expect Nio to dissolve in an aqueous solution of NaNO3?
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Answer:

NiO Does Not Dissolve In An Aqueous Solution Of NaNO3.

Explanation:

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42/19K ——->0/-1e+a/bC
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?

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