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UNO [17]
3 years ago
7

WHEN YOU HEAR THE SIREN OR SEE THE FLASHING RED LIGHT OF A CLOSELY APPROACHING EMERGENCY VEHICLE, AND YOU ARE NOT IN THE INTERSE

CTION, YOU SHOULD:
Physics
2 answers:
MariettaO [177]3 years ago
8 0

When you hear/see an emergency vehicle approaching, you should pull over on the side of the road or into a parking lot immediately until the vehicle passes

Hope this helps

-AaronWiseIsBae

pochemuha3 years ago
5 0
Pull over the side and stop until it passes you. (my opinion)
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Suppose a 49-N sled is resting on packed snow. The coefficient of kinetic friction is 0.11. If a person weighing 585 N sits on t
Andre45 [30]

Answer:

69.74 N

Explanation:

We are given that

Weight of sled=49 N

Coefficient of kinetic friction,\mu_k=0.11

Weight of person=585 N

Total weight==mg=49+585=634 N

We know that

Force needed to pull the sled across the snow at constant speed,F=Kinetic friction

F=\mu_k N

Where N= Normal=mg

F=0.11\times 634=69.74 N

Hence, the force is needed  to pull the sled across the snow at constant speed=69.74 N

7 0
3 years ago
What's the difference in a balanced force in an unbalanced force
AlekseyPX

There's no such thing as one balanced force or one unbalanced force.

If ALL of the forces in a GROUP of forces acting on the same object
all add up to zero, then we say that the GROUP of forces is balanced.

If they don't, then the GROUP of forces is unbalanced.

Two or more forces can be balanced or unbalanced.
One force can't.

7 0
3 years ago
If everything with mass is attracted to every other thing with mass, why doesn’t all the matter in the universe pull together in
kupik [55]

Answer:

i need more info

Explanation:

6 0
3 years ago
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The initial volume reading in a graduated cylinder is 30 mL. The mass of an irregular shape of an unknown metal piece is 55.3 g.
Vadim26 [7]

Answer:

7.9\frac{gr}{cm^3}

Explanation:

When we put the metal piece in the liquid (which is in the graduated cylinder), how much it goes up is equal to the volume of the piece we inserted.

So now we know that the volume of that piece of unknown metal is 7mL (which is the same as 7cm^3).

Density is \frac{mass}{volume}.

So the density of that piece of metal is \frac{55.3g}{7cm^3}

Which leaves us with a final density of 7.9\frac{gr}{cm^3}

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sertanlavr [38]
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4 years ago
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