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3 years ago

In which one or more of the following is the earth assumed to be the center of the universe?

Physics

2 answers:

Virty [35]3 years ago

8 0

Need some more info. Once gotten I'll answer. Ty

sladkih [1.3K]3 years ago

4 0

Can you put the answers, if there are any?
Once you do, Ill respond with a answer asap!
:)

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IIIIIII-PLEASE HELP-IIIIII THERE ARE TWO QUESTIONS (ILL GIVE BRAINLIST)

TiliK225 [7]

Answer:

the answers should be B and D

5 0

3 years ago

Read 2 more answers

1. A bicycle initially moving with a velocity

ki77a [65]

Answer:

$\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}$

Explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

$v_f= v_i+ at$

In this formula, $v_f$ is the final velocity, $v_i$ is the initial velocity, $a$ is the acceleration, and $t$ is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

$\bullet \ v_i = 5.0 \ m/s \\\bullet \ a= 2\ m/s^2\\\bullet \ t= 5 \ s$

Substitute the values into the formula.

$v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)$

Solve inside the parentheses.

$\frac {2 \ m}{s^2}* 5 \ s = \frac{ 2 \ m}{s} * 5 = \frac{ 10 \ m}{s} = 10 \ m/s$

$v_f= 5.0 \ m/s + (10 \ m/s)$

Add.

$v_f= 15 \ m/s$

The units can also be written as:

$v_f= 15 \ m*s^{-1}$

The bicycle's final velocity is 15 meters per second.

7 0

3 years ago

a plane inclined at an angle of 30° to the horizontal has an efficiency of 50%. the force parallel to the plane required to push

Nutka1998 [239]

Answer:

Correct Answer: Option B

Explanation

V.R = 1sinθ=1sin30=21sinθ=1sin30=2

M.A = E×V.R100=50×2100=1E×V.R100=50×2100=1

Effort = loadM.A=1201=120N

3 0

3 years ago

A block of mass M slides down an inclined plane that makes an angle θ with the horizontal. The coefficient of kinetic friction b

Llana [10]

Answer:

Mg Cosθ

Explanation:

mass of block = M

Angle of inclination = θ

coefficient of friction = μk

The force of gravity acts of the block is Mg

there are two components of the weight

the component parallel to the inclined plane is Mg Sinθ

the component perpendicular to the plane of inclined is Mg Cosθ

So, the normal force exerted by the inclined is Mg Cosθ

5 0

4 years ago

Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 re

alexgriva [62]

Answer:

$\frac{Ie}{lm} = 1.10*10^{-3}$

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

$\frac{Ie}{lm} = \frac{-N}{(nf-ni)}$

$\frac{Ie}{lm} = \frac{-(-4.2)}{(12125 - (8325))}$

$\frac{Ie}{lm} = 1.10*10^{-3}$

5 0

4 years ago

Read 2 more answers