If someone with anger issues is struggling to control their temper, great tips are:
1. Find something in your life that you've been through that may relate to what this person is angry about, and calmly share your story. For example, Tom is abnormally angry about not getting his new tool kit delivered on time. So you say, "I understand, one time I waited weeks for my phone case to come in and it upset me very much."
2. Take the angered individual to an isolated and private area. This gives them less triggers and is safer for others.
3. Teach the person coping skills when they are NOT currently having an episode. For example, Chloe is in a good mood while she is painting her nails. So you say, "Can I show you a coping skill for anger I found online? Its awesome! Just tense up every muscle in your body as hard as you can for 5 seconds, then release the tension slowly for 10 seconds. Repeat until you feel cooled down. Try it!"
4. If someone's anger problems become a threat to themselves or those around them, take this person to see a professional. It could be serious!
The answer would be A, since at that position the Earth is fully/partially being engulfed in a shadow cast by the moon from the sun’s rays.
Hope this helps!
The magnitude of the acceleration of block m2 is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.
<h3>Acceleration of the blocks</h3>
The acceleration of the blocks is calculated from the net force on the blocks.
∑F = ma
a = ∑F/m
a = (F) / (m₁ + m₂)
where;
- F is the horizontal force applied
- m₁ is mass of first block = 40 g = 0.04 kg
- m₂ is mass of the second block = 20 g = 0.02 kg
a = (0.03)/(0.04 + 0.02)
a = 0.09 m/s²
<h3>Tension due to block m₂</h3>
T = m₂a
T = (0.02 x 0.09) = 1.8 x 10⁻³ N
Thus, the magnitude of the acceleration of block m2 is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.
Learn more about tension here: brainly.com/question/24994188
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Answer:
Velocity on the right side of the cart 
Explanation:
Given
⇒The mass on the left of the cart 
Its velocity 
,
⇒Mass on the right of the cart 
Velocity
We have to find 
From
The law of conservation of linear momentum:
We can say that.
Initial momentum will equalize the final momentum.
And momentum is the product of mass and its velocity.
Assigning one of its velocity as negative because both are in different direction.
Lets call 
Recalling the formula and plugging the values.
So the velocity of the cart on the right side that has a mass of 
is 
Answer:
0.477 Hz
2.09 s
Explanation:
y = A sin(ωx − φ)
A is the amplitude, ω is the angular frequency, and φ is the phase shift.
ω = 3 rad/s
f = ω / 2π ≈ 0.477 Hz
T = 1/f ≈ 2.09 s
