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2 years ago

Sugar is made of carbon, hydrogen, and oxygen atoms. Sugar is

Physics

2 answers:

Aneli [31]2 years ago

7 0

D. A solution because it dissolves when mixed with water

ZanzabumX [31]2 years ago

6 0

D because it dissolves

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a sphere of diameter 6•0cm is moulded into a thin uniform wire of diameter 0•2mm.calculate the length of the wire in metres

Scilla [17]

The length of the wire is 36 m.

<u>Explanation:</u>

Given, Diameter of sphere = 6 cm

We know that, radius can be found by taking the half in the diameter value. So,

$\text { sphere radius, } R=\frac{D}{2}=\frac{6}{2}=3 \mathrm{cm}=3 \times 10^{-2} \mathrm{m}$

Similarly,

$\text { wire radius, } r=\frac{0.2}{2}=0.1 \mathrm{mm}=1 \times 10^{-3} \mathrm{m}$

We know the below formulas,

$\text {volume of sphere}=\frac{4}{3} \times \pi \times R^{3}$

$\text {volume of wire}=\pi \times r^{2} \times l$

When equating both the equations, we can find length of wire as below, where $\pi=\frac{22}{7}$

$\frac{4}{3} \times \pi \times R^{3}=\pi \times r^{2} \times l$

$\frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-2}\right)^{3}=\frac{22}{7} \times\left(1 \times 10^{-3}\right)^{2} \times l$

The $\pi$ value gets cancelled as common on both sides, we get

$\frac{4}{3} \times 27 \times 10^{-6}=10^{-6} \times l$

The $10^{-6}$ value gets cancelled as common on both sides, we get

$l=4 \times 9=36 m$

7 0

2 years ago

A 63 kg kg person starts traveling from rest down a waterslide 6.0 mm above the ground. At the bottom of the waterslide, it then

gladu [14]

Answer:

change waterslide according to question. and you are good to go. check photo for solve

5 0

2 years ago

What are some evidences of early peoples concern for teeth

Alexandra [31]

Replacement teeth were made even back then out of primitive materials, and pig hair was used like floss

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3 years ago

A test charge is placed at a distance of 2.5 × 10-2 meters from a charge of 6.4 × 10-5 coulombs. What is the electric field at t

Novosadov [1.4K]

Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance.

E = kQ / d²

k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m

Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²

Electric field at the test charge is 921600000 N/C

8 0

2 years ago

Read 2 more answers

A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and ma

Bad White [126]

Length L = 25 cm = 0.25 m, B = 600 G = 0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

5 = emf/ (0.25 T× 0.25 m)

emf = 0.3125 v

Magnetic field

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

To learn more about the magnetic field refer here:

brainly.com/question/23096032

#SPJ4

5 0

1 year ago