Answer:
a) 1.34 Volts
b) 3.08 W
c) 2.68 W
Explanation:
Given:
Emf of the cell, E = 1.54 V
current, i = 2.0 A
internal resistance, r = 0.100Ω
(a) Terminal voltage (V) = E - v
where,
v is the potential difference across the resistance 'r'
now,
according to the Ohm's Law, we have
v = i × r
substituting the values in the above equation we get
v = 2.0 × 0.100 = 0.2 Volts
thus,
Terminal voltage (V) = (1.54 - 0.2) = 1.34 V
(b) Now, the Total power (P) is given as
P = E × i = (1.54 × 2.0) = 3.08 W
(c) Power into its load = [terminal voltage, v] * i
= (1.34 × 2.0) = 2.68 W
Velocity B (relative to the A) = Velocity B (relative to the ground) - Velocity A (relative to the ground)
Velocity B (relative to the ground) = Velocity B (relative to the A) + Velocity A (relative to the ground)
Velocity B (relative to the ground) = 7.5 + 5 = 12 m/s
Since both go up in the same direction, we should use the minus sign for relative velocity.
Answer:
Explanation:
International Bureau of Weights and Measures (BIPM), French Bureau International des Poids et Mesures, international organization founded to bring about the unification of measurement systems, to establish and preserve fundamental international standards and prototypes, to verify national standards, and to determine standard units.
Answer: M^-1 L^-3T^4A^2
Explanation:
From coloumb's law
K = q1q2 / (F × r^2)
Where;
q1, q2 = charges
k = constant (permittivity of free space)
r = distance
Charge (q) = current(A) × time(T) = TA
THEREFORE,
q1q2 = (TA) × (TA) = (TA)^2
Velocity = Distance(L) / time(T) = L/T
Acceleration = change in Velocity(L/T) / time (T)
Therefore, acceleration = LT^-2
Force(F) = Mass(M) × acceleration (LT^-2)
Force(F) = MLT^-2
Distance(r^2) = L^2
From ; K = q1q2 / (F × r^2)
K = (TA)^2 / (MLT^-2) (L^2)
K = T^2A^2M^-1L^-1T^2 L^-2
COLLEXTING LIKE TERMS
T^2+2 A^2 M^-1 L^-1-2
M^-1 L^-3T^4A^2