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fenix001 [56]
2 years ago
9

Which of the species would be expected to be the most miscible in benzene (c6h6)? 1. decane, c10h22 2. hydrogen fluoride, hf 3.

methanol, ch3oh 4. silicon dioxide, sio2 5. sugar, c6h12o6?
Chemistry
2 answers:
max2010maxim [7]2 years ago
7 0

Answer is: 1. decane, c10h22

This pair will most likely form a homogeneous solution because they are both nonpolar substances and "like dissolves like".

Other pairs will not form homogeneous solution because polar (methanol, sugar) or ionic (h<span>ydrofluoric acid)</span> substances have low solubility in nopolar (benzene) substances.

Whitepunk [10]2 years ago
3 0

Decane can be the most miscible species in benzene.

Answer: 1. decane, c10h22

Explanation

The miscibility is the measure of solubility of a solute in a solvent.

As per the rules of solubility, like substances dissolve and unlike substances get suspended.

So here benzene is a non-polar solvent, so the solute which can be most miscible in benzene should also a non-polar nature.

Thus the solute should be non-polar substance to dissolve in non-polar solvent.

Among the options given, decane C10H22 is the non-polar substance which can act as solute.

Thus decane can be the most miscible species in benzene.

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Gas in a balloon occupies 3.3 L. What volume will it occupy if the pressure is changed from 100.0 kPa to 90.0 kPa (at constant t
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Since the temperature is a constant, we can use Boyle's law to solve this.<span>

<span>Boyle' law says "at a constant temperature, the pressure of a fixed amount of an ideal gas is inversely proportional to its volume.

P α 1/V               </span>⇒                 PV = k (constant)<span>

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<span>Here, we assume that the </span>gas in the balloon is an ideal gas. 

We can use Boyle's law for these two situations as,
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By substitution,
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