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3 years ago

Which volume of 0.10m naoh exactly neutralizes 15.0 milliliters of 0.20m hno3?

1 answer:

7 0

The balanced chemical reaction is:

HNO3 + NaOH = NaNO3 + H2O

We are given the amount and concentration of the reactants. The values given will be the starting point.

0.20 mol /L HNO3 (.015 L) (1 mol NaOH / 1 mol HNO3) = 0.003 mol NaOH

0.003 mol NaOH / 0.10 mol/ L NaOH = 0.03 L NaOH or 30 mL NaOH

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_________ is the movement of materials across a cell membrane using cellular energy.

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Answer:

active transport

Explanation:

passive transport does not involve energy

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2 years ago

With the help of balanced chemical equation explain what happens when:(1)Zinc is put in dilute hydrochloric acid (2)Zinc is put

UkoKoshka [18]

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3 years ago

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An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

$m_{solute}$ = Given mass of solute (CsCl) = 8.00 g

$M_{solute}$ = Molar mass of solute (CsCl) = 168.4 g/mol

$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

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3 years ago

92dm3 of a gas dissolved in a solvent. How many moles is this?

Paul [167]

Assuming its at r. t.p and pressure
no. of moles = 96/24=4moles
altho some books will say that its 23.7dm3/mole but that doesnt really matter because its the process that matters

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3 years ago

What is the percentage of lithium in lithium carbonate (Li2CO3)?

ale4655 [162]

Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g

% LI = 13.88/73.89*100 = 18.78% perfectly correct.

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2 years ago

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