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m_a_m_a [10]
2 years ago
11

Write the overall, ionic and net ionic equations for the following reaction. Hydrobromic acid (HBr) and Strontium hydroxide (Sr(

OH)2)

Chemistry
2 answers:
Sophie [7]2 years ago
6 0
I believe this is how you would write the complete ionic and net ionic equations.

LekaFEV [45]2 years ago
3 0
Overaall is a double replacement rxn
2 HBr + Sr (OH)2 》SrBr2 + 2 H2O

ionic just break down into ions and the electrons Don't remember how to write it out

net is without the electrons again don't remember how to write it oir
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Explanation:

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3 years ago
Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid H3PO4 with
VladimirAG [237]

Answer:

7.3 g (NH₄)₃PO₄

Explanation:

The balanced equation for the reaction is:

H₃PO₄ +  3 NH₃ ----> (NH₄)₃PO₄

To find the mass of ammonium phosphate ((NH₄)₃PO₄) produced, you need to (1) convert grams NH₃ to moles NH₃ (via the molar mass from the periodic table), then (2) convert moles NH₃ to moles (NH₄)₃PO₄ (via mole-to-mole ratio from balanced equation), and then (3) convert moles (NH₄)₃PO₄ to grams (NH₄)₃PO₄ (via molar mass from periodic table). Make sure to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 2 sig figs because the given value (2.5 grams) has 2 sig figs.

Molar Mass (NH₃): 14.01 g/mol + 3(1.008 g/mol)

Molar Mass (NH₃): 17.034 g/mol

Molar Mass ((NH₄)₃PO₄):

3(14.01 g/mol) + 12(1.008 g/mol) + 30.97 g/mol + 4(16.00 g/mol)

Molar Mass ((NH₄)₃PO₄): 149.096 g/mol

2.5 g NH₃          1 mole NH₃        1 mole (NH₄)₃PO₄             149.096 g
---------------  x  --------------------  x  ---------------------------  x  --------------------------
                            17.034 g             3 moles NH₃              1 mole (NH₄)₃PO₄

=  7.3 g (NH₄)₃PO₄

8 0
1 year ago
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