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3 years ago

Genes are located in which part of a cell?

Chemistry

2 answers:

guajiro [1.7K]3 years ago

8 0

Answer:

B. Chromosome

Explanation:

Genes are contained in the Chromosome. A Chromosome contains hundreds of thousands of genes.

Vilka [71]3 years ago

7 0

Answer:

Chromosome

Explanation:

We inherit our genes from our parents, which we share 24 chromosomes from both of our parents. XX is female , and XY is male.

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Which of the following names the quantity and correctly explains why that represents the astronauts weight

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3 years ago

Which statement describes a benefit of using fission reactions?

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Calculate the molar mass of a gaseous substance if 0.125 g of the gas occupies 93.3 mL at STP.

just olya [345]

Answer:

30.0g/mol

Explanation:

Step 1: Given data

Mass of the gas: 0.125 g

Pressure (P): 1 atm (standard pressure)

Temperature (T): 273.15 K (standard temperature)

Volume (V): 93.3 mL

Step 2: Calculate the moles of the gas

We will use the ideal gas equation.

$P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{1atm \times 0.0933L}{\frac{0.0821atm.L}{mol.K} \times 273.15K} = 4.16 \times 10^{-3} mol$

Step 3: Calculate the molar mass of the gas

4.16 × 10⁻³ moles correspond to a mass of 0.125 g. The molar mass of the gas is:

$\frac{0.125g}{4.16 \times 10^{-3} mol} =30.0g/mol$

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3 years ago

A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d

g100num [7]

Answer:

0.40 L

Explanation:

Calculation of the moles of $Ba(OH)_2$ as:-

Mass = 51.24 g

Molar mass of $Ba(OH)_2$ = 171.34 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{51.24\ g}{171.34\ g/mol}$

$Moles= 0.2991\ mol$

Volume = 1.20 L

The expression for the molarity is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M$

Thus,

Considering

$Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}$

Given that:

$Molarity_{working\ solution}=0.100\ M$

$Volume_{working\ solution}=1\ L$

$Volume_{stock\ solution}=?$

$Molarity_{stock\ solution}=0.24925\ M$

So,

$0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}$

$Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L$

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

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2 years ago

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