The force acting on the object is constant, so the acceleration of the object is also constant. By definition of average acceleration, this acceleration was
<em>a</em> = ∆<em>v</em> / ∆<em>t</em> = (6 m/s - 0) / (1.7 s) ≈ 3.52941 m/s²
By Newton's second law, the magnitude of the force <em>F</em> is proportional to the acceleration <em>a</em> according to
<em>F</em> = <em>m a</em>
where <em>m</em> is the object's mass. Solving for <em>m</em> gives
<em>m</em> = <em>F</em> / <em>a</em> = (10 N) / (3.52941 m/s²) ≈ 2.8 kg
Answer:
The kinetic energy of the anti proton is 147.4 MeV.
Explanation:
Given that,
Energy = 2.12 GeV
Kinetic energy = 96.0 MeV
We need to calculate the kinetic energy of the anti proton
Using formula of energy

We know that,

So, 

Put the value into the formula


Hence, The kinetic energy of the anti proton is 147.4 MeV.