The movement of the object is considered to be kinetic energy while the object getting warmer indicates that there is thermal (heat) energy formed.
Based on this, as the object slides across the floor, friction slows down this motion and the object becomes warmer as kinetic energy is converted into thermal energy.
I think your question is incomplete because the distance between destination and departure point isn't given in the question
Any change in the speed or direction of motion is called "acceleration". You'll hear "deceleration" used for slowing down but that's not technically correct.
Answer:
The train travelled 10hours.
Explanation:
Using speed= distance/time ...eq1
Let the time taken by train to cover the journey be t.
Let the speed of train be s
Time= distance/speed ...eq2
Time t =600/s ...eq3
The train is delayed for 1 1/2 hours=3/2 hours
Train increased by 15km/hr.
Train travelled 1/4 of 600k.= 150km.
Speed increased by s + 15 to cover the remaining 450km
t = 150/s + 400/(s + 15) + 3/2 ..eq4
Equating eq3 and 4
600/s= 150/s + 460/(s + 15) + 3/2
450/s = 3/2 + 450/(s + 15)
3s^2 + 45s -13500=0
Solving the quadratic equation
S= -45 +-sqrt(45^2-4(3×13500)/2×3
S= 60 , -75
Hence speed of train is 60km/hr
Using eq 2 distance/speed=time
600/60=10
t= 10hours
<h2>Answer:</h2>
<h2>Explanation:</h2>
First, let's refer to the distance formula:
, where d is distance, v is velocity or speed and t is time.
Now, let's find the distance covered by each individual speed that the car had:
<h3>1. Speed 1.</h3>
In order to use the formula, we need to convert minutes into hours since the speed is given in km/h.
21.1 min/60= 0.35 h.
Now, apply the distance formula.
d=(0.35h)*(86.8km/h)= 30.38 km.
<h3>2. Speed 2.</h3>
Convert minutes to hours again and do the same calculations.
10.6min/60=0.18h
d=(0.18h)*(106km/h)= 19.08 km.
<h3>3. Speed 3.</h3>
36.5min/60= 0.61h
d=(0.61h)*(30.9km/h)= 18.85 km.
<h3>4. Obtain the total distance.</h3>
The total distance must be given by the addition of all individual distances traveled by the car on each speed:
Total distance= 30.38 km + 19.08 km + 18.85 km= 68.31 km.
