<span>Let F be the force of gravity, G be the gravitational constant, M be the mass of the earth, m your mass and r the radius of the earth, then:
F = G(Mm / (4(pi)*r^2))
The above expression gives the force that you feel on the earth's surface, as it is today!
Let us now double the mass of the earth and decrease its diameter to half its original size.
This is the same as replacing M with 2M and r with r/2.
Now the gravitational force (F' ) on the new earth's surface is given by:
F' = G(2Mm / (4(pi)(r/2)^2)) = 2G(Mm / ((1/4)*4(pi)*r^2)) = 8G(Mm / (4(pi)*r^2)) = 8F
So:
F' = 8F
This implies that the force that you would feel pulling you down (your weight) would increase by 800%!
You would be 8 times heavier on this "new" earth!</span>
Answer:
the initial velocity of the ball is 104.67 m/s.
Explanation:
Given;
angle of projection, θ = 60⁰
time of flight, T = 18.5 s
let the initial velocity of the ball, = u
The time of flight is given as;
Therefore, the initial velocity of the ball is 104.67 m/s.
Answer:
It has the least potential energy at the bottom of its circular path.
Explanation:
It has the least potential energy at the bottom of its circular path.
Remember the equation
U = m*g*h
where U is the potential energy
m is the mass of the yo-yo
h is the height
Three parts that make up atoms?
1;protons
2;neutrons
3;Electrons
Answer:
increase speed, decrease speed, and change direction
Explanation:
