Answer:
The reaction shifts to the left.
Explanation:
Equilibrium constant (K) = 46.3
Reaction Quotient (Q) = 525
The relationship between Q and K with their implications are given as;
K = Q (No net reaction)
K > Q (Reaction shifts to the right)
K < Q (Reaction shifts to the left)
Since in this question, Q (525) > K (46.3)
The reaction shifts to the left.
The concentrations : 0.15 M
pH=11.21
<h3>Further explanation</h3>
The ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15
![\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7BKb.M%7D%5C%5C%5C%5C%28OH%5E-%5D%3D%5Csqrt%7B1.8%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.15%7D%5C%5C%5C%5C%28OH%5E-%5D%3D%5Csqrt%7B2.7%5Ctimes%2010%5E%7B-6%7D%7D%3D1.64%5Ctimes%2010%5E%7B-3%7D)
![\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21](https://tex.z-dn.net/?f=%5Ctt%20pOH%3D-log%5BOH%5E-%5D%5C%5C%5C%5CpOH%3D3-log~1.64%3D2.79%5C%5C%5C%5CpH%3D14-2.79%3D11.21)
Robert A. Millikan and Harvey Fletcher performed the oil drop experiment.
Answer:
In general, print publications with authors and listed sources tend to be reliable because they provide sources which readers can verify. Likewise, Web postings with a .gov (posted by the United States government) are both current and reliable.
Explanation:
Answer is: osmotic pressure.
Osmotic pressure, alongside the vapor pressure depression, freezing point depression and the boiling point elevation are<span> the </span>colligative properties od solution.
<span>The direction of osmotic pressure is always from the side with the lower concentration (c = n/V) of solute to the side with the higher concentration.</span>
