Now that we have a background in the Lewis electron dot structure we can use it to locate the the valence electrons of the center atom. The valence-shell electron-pair repulsion (VSEPR) theory states that electron pairs repel each other whether or not they are in bond pairs or in lone pairs. Thus, electron pairs will spread themselves as far from each other as possible to minimize repulsion. VSEPR focuses not only on electron pairs, but it also focus on electron groups as a whole. An electron group can be an electron pair, a lone pair, a single unpaired electron, a double bond or a triple bond on the center atom. Using the VSEPR theory, the electron bond pairs and lone pairs on the center atom will help us predict the shape of a molecule.
The shape of a molecule is determined by the location of the nuclei and its electrons. The electrons and the nuclei settle into positions that minimize repulsion and maximize attraction. Thus, the molecule's shape reflects its equilibrium state in which it has the lowest possible energy in the system. Although VSEPR theory predicts the distribution of the electrons, we have to take in consideration of the actual determinant of the molecular shape. We separate this into two categories, the electron-group geometry and the molecular geometry.
Answer:
374°F
463.15K
Explanation:
This particular Question wants to test knowledge on the conversion of the units of temperature from celsius degree to degree Fahrenheit. Also, the conversion of degree celsius to kelvin.
The value given which is 190 degree celsius can be converted into degree Fahrenheit using the formula below;
(x°C × 9/5 ) + 32.
Therefore, x = 190°C =( 190°°C × 9/5) + 32 = 374°F.
The conversion of degree celsius to kelvin is given below as;
x°C + 273.15 .
Therefore, x = 190°C = 190°C + 273.15 = 463.15K.
Therefore, the temperature needed to bake at Fahrenheit and kelvin are 374°F and 463.15K respectively.
Answer:
See the answer below
Explanation:
A decrease in pressure would see a shift in the equilibrium to the left-hand side of the equation.
<em>According to a particular chemical principle, a system in equilibrium that has one of the constraints affecting reactions applied or removed would experience a change in the equilibrium position so as to annul the effects of the application/removal of the constraint.</em>
In this case, 2 moles of NO2 is present on the left-hand side as opposed to 1 mole of N2O4 on the right-hand side. A decrease in pressure will create more space for the formation of NO2 on the left-hand side. Thus, the equilibrium will shift a bit to this side so as to annul the effects of the decrease in pressure.
