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4 years ago

Reduction is reaction which results in a _ in electrons and a(n) __ in positive charge of the atom of ion.

Chemistry

2 answers:

Arlecino [84]4 years ago

7 0

1) gain
(just remember this OIL-Oxidation Is Loss and RIG-Reduction Is Gain)

2) decrease

bekas [8.4K]4 years ago

5 0

Gain,increase
reduction is a reaction in which electron are gained

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hich statement is true? A. An acid with a large pKa will be a better conductor of electricity than one with a smaller pKa. B. An

xz_007 [3.2K]

Answer:

$\boxed{\text{B is correct}}$

Explanation:

Kₐ and pKₐ are measures of the strength of an acid. For example,

HX + H₂O ⇌ H₃O⁺ + X⁻; Kₐ = 10¹⁰, pKₐ = -10

HA + H₂O ⇌ H₃O⁺ + A⁻; Kₐ = 10⁻¹⁰, pKₐ = 10

HX is a strong acid, because it has a larger Kₐ, that is, the position of equilibrium lies far to the right.

However, pKₐ is the negative logarithm of Kₐ, so HX has the smaller pKₐ.

Similarly, Ha is a weak acid, but it has the larger pKₐ.

Strong acid: Large Kₐ ⇔ Low pKₐ

Weak acid: Small Kₐ ⇔ High pKₐ

A is wrong. HA is a weak acid, so it produces only a few hydronium ions.

B is correct. The rate of corrosion depends on the concentration of hydronium ions. HA is a weak acid, so it is less corrosive than an acid with a small pKₐ.

C is wrong. HX is a strong acid, so there are more ions to carry the current. HX will be a good conductor of electricity.

D is wrong. HX is a strong acid, so it provides more hydronium ions and is more corrosive.

E is wrong. HX is a strong acid, so it provides more hydronium ions to stimulate the taste buds.

$\boxed{\textbf{B is correct}}$

7 0

4 years ago

The following are products in the chemical reaction shown below.

scoundrel [369]

Answer:

C₆H₁₂O₆ and O₂

Explanation:

To know which option is correct, it important that we know the concepts of chemical equation .

A chemical equation gives us an expression of a chemical reaction in terms of symbols and formula. There are two sides to every equation. The side bearing the reactant and the side bearing the product.

The reactant is located on the left side and the product is located on the right side.

Reactant —> Product

With the above information, let us answer the question given above.

6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂

The products are located on the right side of the equation.

Thus, the products of the reaction is C₆H₁₂O₆ and O₂

8 0

3 years ago

Draw the structure of the major organic product isolated from the reaction of 1-hexyne with sodium amide in liquid ammonia follo

77julia77 [94]

Answer:check explanation and attached file/picture

Explanation:

Alkynes are hydrocarbons and they are very acidic because of hybridization effect(the more acidic the s-character is, the more acidic it is going to be).

The reaction of 1-hexyne with sodium amide in liquid ammonia is a form of deprotonation 'reaction' to form acetylide. Due to the acidic nature of the terminal hydrogen atom, terminal alkynes do form metallic derivatives by the replacement of the terminal hydrogens. The equation of Reaction is given below.

C6H10 + NaNH2( in liquidNH3) ------------> C6H9Na + H-NH2.

The acetylide is a bae and a very good nucleophile.

The reaction is then followed by the addition of 1-bromobutane. This reaction is used for the production of longer chain alkynes. The equation of Reaction is attached in the picture.