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padilas [110]
3 years ago
7

The sum of two consecutive even integers is 158. Find the least of the two integers.

Mathematics
2 answers:
Mrac [35]3 years ago
7 0

Answer: 78 and 80

Step-by-step explanation:

x + (x + 2) = 158

2x + 2 = 158

-2 -2

2x = 156; divide both sides by 2, and you get x = 78

If x = 78, then x + 2 = 80

djverab [1.8K]3 years ago
6 0

Answer:

78 and 80

Step-by-step explanation:

Two consecutive even integers means that they will go in groups of 2. For example 2 and 4 are consecutive even numbers.

To solve this problem you'll need to set an equation equal to 158. We can call the first even integer x and the second CONSECUTIVE even integer x + 2.

Make these two expressions add up to equal 158 and solve for x.

(x) + (x + 2) = 158

Combine like terms.

2x + 2 = 158

Subtract 2 from both sides of the equation.

2x = 156

Divide both sides of the equation by 2.

x = 78

The first integer is 78, now substitute this value into the expression representing the second integer.

(78) + 2 = 80

The second integer is 80.

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Step-by-step explanation:

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Following solution gives square root of 244:

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