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Eduardwww [97]
3 years ago
5

Which of these elements reacts rapidly when dropped in water?

Chemistry
2 answers:
seraphim [82]3 years ago
8 0
Technically it's grp 1 elements...the answer is ribidium Rb
vazorg [7]3 years ago
5 0

Answer : The correct option is, (a) rubidium (Rb)

Explanation :

The general trend of the reactivity of the metal is,

The reactivity of the metals increases as we go down in the periodic table and the reactivity of the metals decreases as we go from left to right in the periodic table.

Therefore, the reactivity of metal in decreasing order will be,

Rb > Mg > Co > Cd > Ar

As per question, when the given elements dropped in water then the rubidium (Rb) is element which is most reactive that reacts rapidly with the water.

Hence, the element reacts rapidly with water is, rubidium (Rb).

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If the volume of a solid is 100 cm3 and its mass is 400 g, what is its density?
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Under these circumstances, Its density is 4 grams per cm3
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How does a refracting telescope work?
Yakvenalex [24]

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D

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because convex lenses bend light inward

7 0
3 years ago
How do I complete and balance this chemical equation?
GalinKa [24]
I’m I’m pretty sure this is a combustion reaction, so that means the products would be CO2 + H2O.
6 0
3 years ago
The reaction 2A → A2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 M–1min–1. If
Amiraneli [1.4K]

Answer:

0.19M

Explanation:

2A → A2​​​​​

Rate constant = 0.0265 M–1min–1

Initial concentration = 2.00 M

Final Concentration = ?

time, t =  180min

The formular relating the parameters is given as;

1 / [A] = kt + 1 / [A]o

1 / [A] = 0.0265 * 180 + (1 / 2)

1 / [A] = 4.77 + 0.5

[A] = 1 / 5.27 = 0.19M

3 0
3 years ago
If a balloon containing 3000 L of gas at 39C and 99 kPa rises to an altitude where the pressure is 45.5 kPa and the temperature
tiny-mole [99]

Answer:

The answer to your question is below

Explanation:

Data

Volume 1 = V1 = 3000 l

Temperature 1 = T1 = 30°C

Pressure 1 = P1 = 99 kPa

Volume 2 = ?

Temperature 2 = T2 = 16°C

Pressure 2 = P2 = 45.5 kPa

Process

1.- To find the new volume we need to convert the temperature to °K

T1 = 30 + 273 = 303°K

T2 = 16 + 273 = 289°K

2.- Use the Combined gas law

                P1V1/T1 = P2V2/T2

-Solve it for V2

                V2 = P1V1T2 / T1P2

-Substitution

                V2 = (99 x 3000 x 289) / (303 x 45.5)

-Result

                V2 = 85833000 / 13786.5

                V2 = 6225.8 l

There are no conversion factor ratios.

4 0
3 years ago
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