C5H12, pentane, is a liquid at room temperature.

Chemistry

1 answer:

zloy xaker [14]3 years ago

4 0

Answer:

C)We cannot be sure unless we find out its boiling point.

Explanation:

I will like to clearly state that simply comparing two compounds will not tell us exactly which one will be a liquid, solid or gas at room temperature.

If I want to determine whether an unknown substance will be a liquid at room temperature, I will have to measure its boiling point. If the boiling point is above room temperature, and the melting point is below room temperature, it’s a liquid. If the boiling point of the unknown substance is below room temperature, it is a gas.

This confirms that we cannot conclude on the state of matter in which a compound exists unless we know something about its boiling point, not by inspecting the properties of neighbouring compounds in the same homologous series

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. How many grams of Na2SO4 are required to make 2700 mL of a 2.0 M solution?

ratelena [41]

Answer:

Explanation:

From the net ionic equation

Ba2+(aq) + SO42-(aq) ==> BaSO4(s) we see that 1 mole Ba2+ reacts with 1 mole SO42- to -> 1 mol BaSO4

Find moles of Ba2+ used: 0.250 moles/L x 0.0323 L = 0.008075 moles Ba2+

Find moles SO42- present: 0.008075 moles Ba2+ x 1 mol SO42-/1 mol Ba2+ = 0.008075 mol SO42-

Find mass of Na2SO4 present: 0.008075 mol SO42- x 1 mol Na2SO4/1 mol SO42- x 142.04 Na2SO4/mole = 1.14698 g = 1.15 g Na2SO4 (to 3 significant figures)

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2 years ago

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Many different localities are thought to be hotspots, found overlying mantle plumes, although scientists cannot agree on a defin

borishaifa [10]

(If this is correct, can I have Brainlist?)

Answer:

D) anomalous volcanoes such as those in Hawaii

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1 year ago

Why is it necessary to find the percent yield of a reaction? A. to determine the efficiency of the reaction B. to determine the

Sveta_85 [38]

Answer:

Explanation:

Answer:

A. to determine the efficiency of the reaction

Explanation:

Percentage is the ratio of the actual yield to theoretical yield as a percentage. It is calculated by dividing the actual yield by theoretical yield then multiplying by 100%.

Calculation of percentage yield is important as it helps in the determination of efficiency of a reaction. For example in most industries for the purpose of making the most product with the least waste.

Additionally, calculating the percentage yield helps in determining other products that may be formed during the reactions.

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2 years ago

A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask ab

77julia77 [94]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

By definition, $pH = -log[H_3O^+]$ .
NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: $NaOH (aq)\rightarrow Na^+ (aq) + OH^- (aq)$ .
From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: $[NaOH] = [OH^-]$ .
Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: $[OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}$ .
We also know that $pOH = 14.00 - pH = -log[NaOH]$ . Take the antilog of both sides: $10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}$ .
Solve for the mass of NaOH: $m_{NaOH} = 10^{pH - 14.00}\cdot M_{NaOH}\cdot V$ .