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3 years ago

If two objects move farther apart from one another, the force of gravity will

Physics

2 answers:

Readme [11.4K]3 years ago

6 0

the answer is b

decrease

jonny [76]3 years ago

4 0

Gravity is universal. This force of gravitational attraction is directly dependent upon the masses of both objects and inversely proportional to the square of the distance that separates their centers. This means that as you move away from an object the gravitational force decreases.

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150 ml of water is heated with a burning marshmallow From 20 c to 93.5 C

kap26 [50]

93.5 if it’s wrong sorry sis I need my homework done too

7 0

3 years ago

Directions Part 2: Using what you learned about the formation of the Grand Canyon and which layer is oldest, try to answer the f

kykrilka [37]

Answer: Neighbour

Explanation: Taken perspective from the given clues:

The Neighbor walks to work

The Handyman rides a bike

The Cook rides a motorcycle

The Maid drives a car

The Nephew has a dog

If we assume that the handyman delivered the iPad in the mailbox, then

The direction of the cook, Nephew and his dog are perpendicular to the direction of the bike of the handyman. So, it can't be the cook, Nephew and the maid.

The two suspects are the handyman and the neighbour.

If the handyman actually dropped the iPad and left, then, the neighbour should be the culprit.

8 0

4 years ago

On a very muddy football field, a 110kg linebacker tackles an 85kg halfback. Immediately before the collision, the linebacker is

ololo11 [35]

Answer:

A. the magnitude of the velocity at which the two players move together immediately after the collision is 7.9m/s

B. The direction of this velocity is due north as the linebacker since he has obviously has more momentum

Explanation:

This problem bothers on the inelastic collision

Given data

Mass of linebacker m1= 110kg

Mass of halfbacker m2= 85kg

Velocity of linebacker v1= 8.8m/s

Velocity of halfbacker v2= 7.2m/s

Applying the principle of conservation of momentum for inelastic collision we have

m1v1 +m2v2= (m1+m2)v

Where v is the common velocity after impact

Substituting our data into the expression we have

110*8.5+85*7.2= (110+85)v

935+612=195v

1547=195v

v=1547/195

v=7.9m/s

Momentum of linebacker after impact = 110*7.9= 869Ns

Momentum of halfbacker after impact = 85*7.9= 671.5Ns

the direction after impact is due north since the linebacker has greater momentum

5 0

4 years ago

A lead ball is dropped into a lake from a diving board 16.0 ft above the water. It hits the water with a certain velocity and th

BlackZzzverrR [31]

Answer:

138.46 ft

Explanation:

When the ball is dropped until the moment it hits the water, the ball moves in a uniform acceleration motion. Therefore, the equation that describes the movement of the ball is:

$X = \frac{1}{2}*g*t^{2} + V_{0} *t + x_0$

Where X is the distance that the ball has fallen at a time t. $V_0$ is the initial velocity, which is 0 ft/s as the ball was simply dropped. $x_0$ is the initial position, we will say that this value is 0 in the position where the ball was dropped for simplicity, and it increases as the ball is falling. Now, we replace x with 16 feets and solves for t:

$16 ft = \frac{1}{2} * 32.2 \frac{ft}{s^{2}} *t^{2} +0 \frac{ft}{s} * t + 0 ft$

$t = \sqrt{2* \frac{16 ft}{32.2 \frac{ft}{s^2}}} = 1 s$

The velocity that the ball will have at the moment the ball that the ball hits the water will be:

$V = V_o+g*t=0\frac{ft}{s}+32.2\frac{ft}{s^2}*1s =32.2\frac{ft}{s}$

The time that will take the ball to reach the bottom from the top of the lake will be t = 5.3s - 1s = 4.3s. And as the ball will travel with constant velocity equal to 32.2 ft/s^2, the depth of the lake will be:

$d = v*t = 32.2\frac{ft}{s} * 4.3s = 138.46 ft$