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antiseptic1488 [7]
3 years ago
9

A compact disc has a radius of 6 centimeters.

Physics
2 answers:
Vika [28.1K]3 years ago
5 0
Circumference is 2\pi{r}=37.7 (approx.)
Speed is 4 times that. That is, 150.8 cm/s or 1.508 m/s.
If we get a point at distance 3 cm, we take the radius half of that. The circumference also gets half, so does the linear speed. We get 0.754 m/s or 75.398 cm/s.
alex41 [277]3 years ago
5 0

Answer:75.389

Explanation:

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during a space shuttle launch about 830,000 kg of fuel is burned in 8 min. the fuel provides the shuttle with a constant thrust,
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The shuttles acceleration in the creases as the fuel is burned because the acceleration of the obect as produced by net force is directly proportional to the magnitude of the net force.
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What is the similarities of a furnace and the sun?
Svetlanka [38]

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They are both extremely hot, they both produce a form of light, they both have/use fire(typically)

Explanation:

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If the velocity is 50 and the time is 5 seconds what is the acceleration?
disa [49]

Just divide the both, you will get the answer!

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im sorry for that!

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if the kinetic and potential energy in a system or equal to the potential energy increases what happens as a result
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Answer:If the kinetic and potential energy in a system are equal, then the potential energy increases. ... Stored energy decreases. Energy of motion decreases. Total energy decreases

Explanation:

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3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
Galina-37 [17]

Answer:

220 A

Explanation:

The magnetic force on the floating rod due to the rod held close to the ground is F = BI₁L where B = magnetic field due to rod held close the ground = μ₀I₂/2πd where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, I₂ = current in rod close to ground and d = distance between both rods = 11 mm = 0.011 m. Also, I₁ = current in floating rod and L = length of rod = 1.1 m.

So, F = BI₁L

F = (μ₀I₂/2πd)I₁L

F = μ₀I₁I₂L/2πd

Given that the current in the rods are the same, I₁ = I₂ = I

So,

F = μ₀I²L/2πd

Now, the magnetic force on the floating rod equals its weight , W = mg where m = mass of rod = 0.10kg and g = acceleration due to gravity = 9.8 m/s²

So, F = W

μ₀I²L/2πd = mg

making I subject of the formula, we have

I² = 2πdmg/μ₀L

I = √(2πdmg/μ₀L)

substituting the values of the variables into the equation, we have

I = √(2π × 0.011 m × 0.1 kg × 9.8 m/s²/[4π × 10⁻⁷ H/m × 1.1 m])

I = √(0.01078 kgm²/s²/[2 × 10⁻⁷ H/m × 1.1 m])

I = √(0.01078 kgm²/s²/[2.2 × 10⁻⁷ H])

I = √(0.0049 × 10⁷kgm²/s²H)

I = √(0.049 × 10⁶kgm²/s²H)

I = 0.22 × 10³ A

I = 220 A

7 0
3 years ago
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