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Elina [12.6K]
3 years ago
15

How does every singles cell in the body get the substances it needs to carry out the chemical reaction that provides it with ene

rgy?
Chemistry
2 answers:
skelet666 [1.2K]3 years ago
8 0
Are you just asking how the body gets substances that it requires to carry out cellular respiration ?

If yes then the formula for cellular respiration is glucose + oxygen = water + CO2 + ATP (energy).
How body gets glucose :
When the stomach digests food, the carbohydrate (sugars and starches) in the food breaks down into another type of sugar, called glucose. The stomach and small intestines absorb the glucose and then release it into the bloodstream. Then the glucose is then let into the cell through the cell membrane and proteins ( active transport , facilitated diffusion)
For oxygen we just breathe it in and oxygen is then let into our cells through the cell membrane ( diffusion ) .
Lesechka [4]3 years ago
3 0
And I don't exactly get what you are trying to ask hit me back up though
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Which principle goes against Bohr's theory and why??​
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Answer:

As the Bohr's fixed orbit gives precise information about the radial position and momentum of the orbit, it is against the Heisenberg uncertainty principle. Thus it is inferred that the Heisenberg uncertainty principle goes and the concept Bohr's fixed Orbit are opposite to each other.

Explanation:

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3 years ago
What does the second law of thermodynamics say about entropy
alukav5142 [94]

Answer:

The entropy and the systems surrounding it tend to increase.

5 0
2 years ago
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Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
Water will melt faster on a very cold soft drink can than it will on a cool soft drink is this physical or chemical change?
Margarita [4]
I believe its chemical change


hope this helps
7 0
3 years ago
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What is the volume of 0.80 grams of O2 gas at STP? (5 points) Group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l
Anarel [89]

Answer:

0.56 liters

Explanation:

First we <u>convert 0.80 grams of O₂ into moles</u>, using its molar mass:

  • 0.80 g ÷ 32 g/mol = 0.025 mol

At STP, 1 mol of any given mass occupies 22.4 L. With that information in mind we <u>calculate the volume that 0.025 moles of O₂ gas would occupy</u>:

  • 0.025 mol * 22.4 L/mol = 0.56 L

Thus the answer is 0.56 liters.

3 0
2 years ago
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