Answer:
Right
Explanation:
The given parameters are;
The soluble sulfate formed by the metal, M = M₂SO₄
In the galvanic cell formed by the metal M, we have;
The concentration of M₂SO₄ in the left half cell = 50.0 mM = 0.05 M
The concentration of M₂SO₄ in the right half cell = 5.00 M
In the galvanic cell, the metal 'M' will be dissolved into the solution with lower concentration as M²⁺ which is the left half cell, making the cell negative and the solution more concentrated
In the right half cell, the metal 'M²⁺' in the solution will be plated unto the electrode making the solution less concentrated and the electrode in the right half cell will be the positive electrode
Therefore;
The electrode which will be positive is the electrode in the right half cell.
Answer:
A
Explanation:
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Answer:
Rate of reaction = 2.0 M/s
Explanation:
2H2O2(g) --> 2H2O(g) + O2(g)
Rate of formation of H2O = 2.0 M/s
Rate of reaction can be measured using multiple techiques and parameters like volume, pressure etc.
Among these techniques is the measurement of appearance of products.
This means we have;
Rate of reaction = Rate of appearance of product
Hence;
Rate of reaction = 2.0 M/s
At STP (standard temperature and pressure conditions), 1 mol of any gas occupies 22.4 L
This rule is applied to O₂
22.4 L volume occupied by 1 mol
Therefore 83.4 L occupied by - 1/ 22.4 x 83.4 = 3.72 mol
stoichiometry of O₂ to H₂O is 1:2
then the number of moles of water produced - 3.72 mol x 2= 7.44 mol
mass of water produced - 7.44 mol x 18.01 g/mol = 134.1 g
correct answer is D
