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alukav5142 [94]
3 years ago
15

The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the valu

e mathematically, and check it using the number line.

Physics
2 answers:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is -0.50 meter/second.

The change in velocity for ball 1 is -0.50 – 1.00 = -1.50 meters/second.

Explanation:

yee hope it helps

djverab [1.8K]3 years ago
5 0

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.

The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds

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A uniform electric field with a magnitude of 5750 N/C points in the positive x direction. Find the change in electric potential
castortr0y [4]

Explanation:

Given that,

Electric field = 5750 N/C

Charge q=+10.5\times10^{-6}\ C

Distance = 5.50 cm

(a). When the charge is moved in the positive x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot d

\Delta U=-q(E\cdot d)

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times5.50\times10^{-2}

\Delta U=-3.32\times10^{-3}\ J

The change in electric potential energy  is -3.32\times10^{-3}\ J

(b). When the charge is moved in the negative x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot (-d)

\Delta U=-q(E\cdot (-d))

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times(-5.50\times10^{-2})

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The change in electric potential energy  is 3.32\times10^{-3}\ J

Hence, This is the required solution.

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