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ycow [4]
3 years ago
12

Which quantities define momentum?

Physics
1 answer:
grigory [225]3 years ago
7 0

Answer:

A. How much matter an object has, plus the magnitude and direction  of its motion

Explanation:

Momentum is defined as the product of mass by velocity, in the international system of measurements (SI) momentum has the following Units [kg*m/s].

P = m*v

where:

P = momentum Lineal [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Therefore the answer is A) How much matter an object has, plus the magnitude and direction  of its motion

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The joule (J) is a unit of energy. Recall that energy may be converted between many different forms such as mechanical energy, t
REY [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The workdone is  W = -177.275J

Explanation:

From the question we are told that

      The initial Volume is  Vi = 0.160 L

      The final volume is  V_f = 0.510L

      The external pressure is  P = 5.00 \ atm

Generally the change in volume is

           \Delta V = V_f - V_i

Substituting values we have

           \Delta V = 0.510 -0.160

                 = 0.350L

Generally workdone is mathematically represented as

           W = -P \Delta V

W is negative because the working is done on the environment by the system which is indicated by volume increase

     Substituting values

                W = - 5* 0.350

                    = -1.75 \ L \ \cdot atm

Now  1 \  L \cdot atm = 101.3J

  Therefore  W = -1.75* 101.3

                          = -177.275J

   

7 0
3 years ago
Read 2 more answers
A go-cart is rolling down a hill at 15m/s. If it has 85J of kinetic energy. what is the mass of the go-cart?
hichkok12 [17]
0.76kg !!!!! I hope it right
3 0
2 years ago
Pls help me with this fast. I will mark brainiest
denis23 [38]

Answer:

a) 70, 95

b) 95-70= 25cc

c) density= mass/volume

102/25

=4.08g/cc

5 0
3 years ago
Please help willing to give brainliest
-Dominant- [34]

Answer:

sound water because sound is the most important electronic wave for water

6 0
3 years ago
In a lab experiment a light flexible string is wrapped around a solid cylinder with mass M = 9.50 kg and radius R. The cylinder
Lunna [17]

Answer:3.79 m/s^2

Explanation:

Given

Mass M=9.5 kg

m=3 kg

Net Force is equivalent to \sum F=ma

with tension T in the string    

For mass m

mg-T=ma

T=mg-ma--------1

For cylinder

T\cdot R=I\times \alpha

I for solid cylinder is \frac{2}{5}MR^2 , and \alpha =\frac{a}{R}

thus T=\frac{Ma}{2}----2

Substitute the value of T we get

\frac{Ma}{2}=mg-ma

a(\frac{M}{2}+m)=mg

a=\frac{mg}{\frac{M}{2}+m}

a=3.79 m/s^2

5 0
3 years ago
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