Actual distance between earth and sun: 1 AU
Supposed distance: 4 AU
Given that the gravitational force is inverse to the square of the distance that separate the masses, this would be weaker if the distance is greater.
Here you hava a mathematical demonstration:
Gravitational force α 1/r^2 (α is used to indicate proportionality)
Actual Force / [1 /(1AU)^2] = New Force / [1 / (4AU)^2]
=> New Force = [1 / 16 AU^2 ] * Actual Force / [1 / 1 AU^2]
New Force = Actual Force / 16
Then, the new force would be weaker; exactly it would be one sixteenth of the actual force.
Answer:
72 Nm²
Explanation:
work = F . d
work = (12i ,0j) . (6i ,-8j )
work = 72 J
The 12N force is a vector acting in the direction of the positive x axis, so its vector notation is 12i + 0j.
It's not exactly clear what the point's location is but I interpret it to be x= m*6, y= -m*8 (I hope the "m" wasn't a typo). The direction vector from the origin is then m*6i -m*8j
When a force vector F acts in a nonparallel direction d, the work is given by:
W = |F|*|d|*cos(theta) where theta is the angle between the vectors.
alternatively you can use the dot product of the two vectors to get:
W = (12N)*(m*6) + (0N)*(-m*8) = 72 Nm²
Answer:
Refractive index is 1.43
Explanation:
We are given;
- The speed of light through a material as 2.1 × 10^8 m/s
We are required to determine the refractive index of the material.
- We need to know refractive index may be given by the formula;
- Refractive index = Speed of light in air ÷ speed of light in a material
The speed of light in air is 3.0 × 10^8 m/s
Therefore;
Refractive index = 3.0 × 10^8 m/s ÷ 2.1 × 10^8 m/s
= 1.4286
= 1.43
Thus, the refractive index of the material is 1.43
Its b<<<<<<<<<<<<<<<<<<<<,\
Answer: I'm not sure, but I think it would be a <em>total lunar eclipse </em>