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Artemon [7]
3 years ago
13

What volume will 0.405 g of krypton gas occupy at STP?

Chemistry
2 answers:
Rufina [12.5K]3 years ago
8 0

Answer:

The answer to your question is V = 0.108 L or 108 ml

Explanation:

Data

Volume = ?

mass = 0.405 g

Temperature = 273°K

Pressure = 1 atm

Process

1.- Convert mass of Kr to moles

                  83.8 g of Kr -------------------- 1 mol

                     0.405 g     -------------------  x

                     x = (0.405 x 1) / 83.8

                     x = 0.0048 moles

2.- Use the Ideal gas law to solve this problem

                   PV = nRT

- Solve for V

                      V = nRT / P

- Substitution

                      V = (0.0048)(0.082)(273) / 1

- Simplification

                       V = 0.108 / 1

- Result

                       V = 0.108 L

Ganezh [65]3 years ago
4 0

Answer:

The volume of the krypton gas is 108.2 mL

Explanation:

Step 1: Data given

Mass of krypton = 0.405 grams

STP = 1 atm , 273 K

Atomic mass krypton = 83.80 g/mol

Step 2: Calculate moles of krypton

Moles krypton = mass krypton /molar mass krypton

Moles krypton = 0.405 grams / 83.80 g/mol

Moles krypton = 0.00483 moles

Step 3: Calculate volume of krypton gas

p*V = n*R*T

V = (n*R*T)/p

⇒with n = the moles of krypton =0.00483 moles

⇒with R = the gas constant = 0.08206 L*atm/L*mol

⇒with T = the temperature = 273 K

⇒ with p = the pressure = 1 atm

⇒ with V = the volume of the krypton gas = ?

V = 0.00483 * 0.08206 * 273

V = 0.1082 L = 108.2 mL

The volume of the krypton gas is 108.2 mL

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The number of moles of KF needed to prepare the solution is 3 moles

<h3>What is molarity?</h3>

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

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<h3>How to determine the mole of KF </h3>
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A gas occupies a volume of 60 L at a temperature of 0.5 K. What will the volume be at 4 K?
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Answer:

480 L

Explanation:

In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.

As we can see, Charles's Law is:

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

or, initial volume over initial temperature equals final volume over final temperature.

In this question, 60 L is our <u>initial volume,</u> and 0.5 K is our <u>initial temperature</u> (K being Kelvin). We are only given 4 K as our <u>final temperature</u>. We are asked to solve for the <u>final volume</u>. Let's set up the equation and solve for V_{2}:

--------------------------------------------------------------------------------------------------------------

(60) / (0.5) = V_{2} / (4)

↓

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×4           ×4

↓

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There's our answer! Feel free to comment if you have any questions about my answer :)

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