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VashaNatasha [74]
3 years ago
14

Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po

larizing filter whose axis is at 40.0∘∘ to that of the first. Determine the intensity of the beam after it has passed through the second polarizer. g
Physics
1 answer:
zvonat [6]3 years ago
5 0

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

I_2=I_1 cos^2 \theta

where

\theta is the angle between the axes of the two polarizer

Here we have

\theta=40^{\circ}

So the intensity after the 2nd polarizer is

I_2=I_1 (cos 40^{\circ})^2=0.587I_1

And substituting the expression for I1, we find:

I_2=0.587 (\frac{I_0}{2})=0.293I_0

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Only four forces act on an object. They all have the same magnitude. Their directions are north, south, northwest, and northeast
mina [271]

Answer:

the correct answer is A,   North

Explanation:

The forces are vectors so they must be added vectorially.

The magnitude of the forces is the same, but not their direction, which is why they are different.

Analyze the situation presented

We have a force towards the North and another towards the South with the same magnitude, therefore these cancel each other out

We have a force towards the Northeast and another towards the Northwest, these can be decomposed into parts, one towards the North and another on the East-West axis, this last component is canceled, but the component towards the North is added.

In summary we see that the body accelerates towards the North

the correct answer is A

7 0
3 years ago
a sealed cylinder contains a sample of ideal gas at a pressure of 2.0 atm. The rms speed of the molecules is v0. If the rms spee
fredd [130]

Answer:

P_2 = 1.62 atm

Explanation:

We know the formula for the rms speed of the ideal gas is  given by

v_{rsm}=\sqrt{\frac{3PV}{m} }

P= pressure of the surrounding

V= volume of the vessel

m= mass of the gas

Now, From this formula rms speed (v_rms) is directly proportional to square root is pressure.

Then  

\frac{v_{rsm,1}}{v_{rsm,2}} =\sqrt{\frac{P_1}{P_2} }

given that v_rsm,1= v0

and v_rsm,2=0.9v0

putting these values we get

\frac{v0}{0.9v0} =\sqrt{\frac{2}{P_2} }

P_2 = 1.62 atm

8 0
3 years ago
Read 2 more answers
You recently purchased a home four blocks from the busy tollway. On a typical evening, the decibel level resulting from tollway
inn [45]

Answer:

74dB

Explanation:

Sound intensity is inversely proportional to the square of the distance. Thus, a house four times closer hears a sound 16x more intense.

The dB scale is logarithmic, so 16x louder than 62 dB is equal to

62 + 10*log(16) ~= 62 + 12 = 74dB

5 0
3 years ago
How many 176 ohm resistors are connected in series to get a current of 5 a on 220 v battey
Phantasy [73]
Total resistance = voltage / current = 220 / 5 = 44 ohms .

Even one 176-ohm resistor is too much.  The current through it is 1.25 A,
and more than one of them in series reduces the current even further.

Connecting them in <em><u>parallel</u></em>, however . . .

Four resistors of 176-ohms each, in <u>parallel</u>, have a net effective resistance
of 176/4 = 44 ohms ... exactly what you need to do the job.

4 0
3 years ago
A source emits sound of wavelengths 2. 64 m and 2. 72 m in air.
andreyandreev [35.5K]

(a) If a source emits sound of wavelengths 2. 64 m and 2. 72 m in air, 4 beats per second will be heard.

(b)The maximum intensity regions are apart by 90 m (approx).

Given,

Wavelengths of sound waves emitted by the source are respectively  = 2.64 m and λ2 = 2.72 m

(a) As the measurement of the beats per second is equal to the frequency difference of the overlapping two sound waves,

Therefore, the frequency difference of the two waves is,

Δf =(f_{1} -f_{2})

where f_{1} and f_{2 } are the frequencies of waves of wavelength λ1 and λ2

Now, speed of sound in air at temperature t = 20° C, is v = 343 m/s

∴ Δf = (f_{1} -f_{2})

⇒Δf = \frac{v}{\lambda1}-\frac{v}{\lambda2}  \\

⇒Δf =\frac{343}{2.64} -\frac{343}{2.72\\}=3.82

⇒Δf ≅ 4

Hence 4 beats per second will be heard.

(b)  When two waves overlap in the same phase in a region the intensity of that region becomes maximum due to constructive interference.

For constructive interference, the path difference is = nλ

Therefore the difference between the maximum intensity regions is given by,

d = \frac{v}{\Delta f} = \frac{343}{3.82\\}= 89.79

⇒d≅90 m

Hence the maximum intensity regions are apart by 90 m (approx).

Learn more about constructive interference on

brainly.com/question/22882887

#SPJ4

6 0
1 year ago
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