Question

Chegg A uniform solid disk of mass m = 3.01 kg and radius r = 0.200 m rotates about a fixed axis perpendicular to its face with angular frequency 5.97 rad/s. (a) Calculate the magnitude of the angular momentum of the disk when the axis of rotation passes through its center of mass. kg · m2/s (b) What is the magnitude of the angular momentum when the axis of rotation passes through a point midway between the center and the rim? kg · m2/s

Answer 1

Answer with Explanation:

We are given that

Mass=3.01 kg

Radius,r=0.2 m

Angular frequency,$\omega=5.97 rad/s$

a.Angular momentum,$L=I\omega=\frac{1}{2}mr^2\omega=\frac{1}{2}(3.01)(0.2)^2(5.97)=0.36 kgm^2/s$

b.When the axis of rotation passes through a point midway between the ceneter and rim then moment of inertia,I=$\frac{3}{4}mr^2$

Angular momentum,$L=\frac{3}{4}(3.01)(0.2)^2(5.97)=0.55 kgm^2/s$