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maksim [4K]
4 years ago
10

Chegg A uniform solid disk of mass m = 3.01 kg and radius r = 0.200 m rotates about a fixed axis perpendicular to its face with

angular frequency 5.97 rad/s. (a) Calculate the magnitude of the angular momentum of the disk when the axis of rotation passes through its center of mass. kg · m2/s (b) What is the magnitude of the angular momentum when the axis of rotation passes through a point midway between the center and the rim? kg · m2/s
Physics
1 answer:
ipn [44]4 years ago
8 0

Answer with Explanation:

We are given that

Mass=3.01 kg

Radius,r=0.2 m

Angular frequency,\omega=5.97 rad/s

a.Angular momentum,L=I\omega=\frac{1}{2}mr^2\omega=\frac{1}{2}(3.01)(0.2)^2(5.97)=0.36 kgm^2/s

b.When the axis of rotation passes through a point midway between the ceneter and rim then moment of inertia,I=\frac{3}{4}mr^2

Angular momentum,L=\frac{3}{4}(3.01)(0.2)^2(5.97)=0.55 kgm^2/s

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The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very
BabaBlast [244]

Answer:

The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker.

Explanation:

A magnetic brakes is not a very efficient way of braking when a train is moving slowly because at low speeds, the changes in the magnetic flux are very less and so it causes the eddy current to become weaker.

Let us find the drag force which is proportional to the velocity of two conducting plates.

The EMF that is induced in the eddy currents are : $E=v(B \times L)$

The force which is due to the induced magnetic field is, $F=l(L \times B)$

Therefore, $F=\frac{E}{R} \times (L \times B)$

                 $F=\frac{v(B \times L)}{R} \times (L \times B)$

Here, force is directly proportional to the velocity of the two conducting plates.

Therefore, we can say that when the speed of the train is low, the magnetic flux changes are less and thus the eddy currents are weaker.  

6 0
3 years ago
Which of the following is not a sedimentary structure?A) Magma emplacementB) Mud cracksC) Ripple marksD) Cross beds
lawyer [7]

Answer:

A) Magma emplacement

Explanation:

Sedimentary structures forms during deposition of sediments. It can also form after sediments have been deposited. Sedimentary structures can only be found in sedimentary rocks. Some examples include mud cracks, ripple marks, cross stratification, potholes, etc

Magma emplacement is an igneous process which describes the different mechanisms by which magma can be emplaced. It is only typical of igneous rocks.

6 0
3 years ago
Explain how the gravitational potential energy of an object can be changed.
inna [77]

Answer:

Change in Potential energy, pe = Final potential energy - Initial potential energy

Explanation:

∆p.e = Final p.e - Initial p.e

From the equation ∆p.e = (mgh) final - (mgh) initial

4 0
3 years ago
a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
What is electricity?​
const2013 [10]

Explanation:

electricity is the flow of electrical power or charge

4 0
3 years ago
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