A)
R1 = 30/(7*60)
We are multiplying 7 with 60 because there are 60 seconds in 1 minute.
R1 = 30/420 = 0.0714 gallons/second
b) For this we need to express gallons to cubic meters.
1 gallon = 0.003785 m^3
R2 = 0.0714*0.003785 = 0.00027 m^3/s
c) V = R2*t where V is volume of some tank.
which means that
t=V/R2
t = 3698.8s or
t = 1.0274 hours
Answer:
807.88N/m
Explanation:
<em>The question has some missing details in it, nevertheless, based on the given data we want to find the spring constant K</em>
Step one
given data
Unstretched length = 33.5 cm
Final length of the spring = 42.0 cm
Δx= 42-33.5
Δx=8.5cm to m= 0.085m
mass m= 7kg
The force on the spring
F=mg
F= 7*9.81
F=68.67N
Step two:
From Hooke's law, we can make k subject of formula and find the spring constant k, we have
F=kΔx---------1
make k subject of the formula
k=F/Δx
k= 68.67/ 0.085
k=807.88N/m
Answer: hypothesis that is not supported by the results of an experiment may lead to further research and investigations.
