Answer:
2.24 Liters are in 4.4 grams of CO2 at STP
The molarity of a salt solution made by dissolving 250.0 grams of NaCl in 775 mL of solution is <u>5.52 M</u> .
<u>Explanation:</u>
The molarity of a solution tells one how many moles of <u>solute</u> one can get <em>per liter</em> of solution.One should remember to must convert this volume to liters by using the conversion factor:
1 L = 10³ml
Sodium chloride (NaCl) has a molar mass of 58.44 g per mol , which means that the sample will contain:

This means that the molarity of the solution will be:

Answer:
[Ba^2+] = 0.160 M
Explanation:
First, let's calculate the moles of each reactant with the following expression:
n = M * V
moles of K2CO3 = 0.02 x 0.200 = 0.004 moles
moles of Ba(NO3)2 = 0.03 x 0.400 = 0.012 moles
Now, let's write the equation that it's taking place. If it's neccesary, we will balance that.
Ba(NO3)2 + K2CO3 --> BaCO3 + 2KNO3
As you can see, 0.04 moles of K2CO3 will react with only 0.004 moles of Ba(NO3) because is the limiting reactant. Therefore, you'll have a remanent of
0.012 - 0.004 = 0.008 moles of Ba(NO3)2
These moles are in total volume of 50 mL (30 + 20 = 50)
So finally, the concentration of Ba in solution will be:
[Ba] = 0.008 / 0.050 = 0.160 M
Answer:
En el caso del sodio, la valencia es 1, ya que tiene un solo electrón de valencia, si pierde un electrón se queda con el último nivel completo.
Explanation:
Grupo de la tabla periódica Electrones de valencia
Grupo 14 (IV) (Grupo del carbono) 4
Grupo 15 (V) (Grupo del nitrógeno ) 5