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Aliun [14]
3 years ago
8

A sound from a source has an intensity of 270 dB when it is 1 m from the source.

Physics
1 answer:
Rufina [12.5K]3 years ago
8 0
Remember that sound intensity decreases in inverse proportion to the distance squared. So, to solve this we are going to use the inverse square formula: \frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
where
I_{2} is the intensity at distance 2
I_{1} is the intensity at distance 1
d_{2} is distance 2
d_{1} is distance 1

We can infer for our problem that I_{1}=270, d_{1}=1, and d_{2}=3. Lets replace those values in our formula to find I_{2}:
\frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
\frac{I_{2} }{270} =( \frac{1}{3} )^2
\frac{I_{2} }{270} = \frac{1}{9}
I_{2}= \frac{270}{9}
I_{2}=30 dB

We can conclude that the intensity of the sound when is <span>3 m from the source is 30 dB.</span>
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