All categories

3 years ago

A transverse wave is propagated in a string stretched along the x-axis. The equation of the wave, in SI units, is given by:

Physics

1 answer:

irina [24]3 years ago

6 0

Answer:

The wave speed in SI units, is closest to - 2.7 m/s

Explanation:

given information:

y = 0.005 cos [π(38t - 14x)]

we know that the wave function is

y = A cos (kx ± ωt)

where

A = amplitude

w = angular velocity

k = wave number

thus,

y = 0.005 cos [(14πx - 38πt)]

ω = - 38π

k = 14π

to find the speed v, we use the equation below

v = ω/k

so,

v = - 38π/14π

= - 2.7 m/s

You might be interested in

Semenov [28]

Ionic bond: it is also called "electrovalent bond". It is "a type of chemical bond that can often form between metal and non-metal ions through electrostatic attraction";

Covalent bond is a form of chemical bonding, "characterized by the sharing of pairs of electrons between atoms, or between atoms and other covalent bonds";

Metallic bond: "the chemical bond, which is characteristic of metals, in which mobile valence electrons are shared among atoms in a usually stable crystalline".

4 0

3 years ago

How many electrons are in the third energy level? 2 8 18 20

Blababa [14]

Answer:

B)8

Explanation:

In the first energy level you can have, at most, 2. Every energy level after that wants to have 8 electrons. Valence electrons I believe.

Hope this helps, have a nice day! (^-^)

6 0

3 years ago

Read 2 more answers

Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. what is the truck’s velocity?

klasskru [66]

The momentum of an object is the product between the mass m of the object and its velocity:
$p=mv$
The truck in our problem has momentum equal to
$p=40120 kg m/s$
and a mass of
$m=1180 kg$
so, if we re-arrange the previous formula, we can use these data to find the velocity of the truck:
$v= \frac{p}{m}= \frac{40120 kg m/s}{1180 kg}=34 m/s$

5 0

3 years ago

Read 2 more answers

A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu

vredina [299]

Answer:

a) $v_1=5.5172\ m.s^{-1}$

b) $v_2=-1.5152\ m.s^{-1}$

c) $v_3=4.6154\ m.s^{-1}$

d) $v_{avg}=3.8462\ m.s^{-1}$

Explanation:

Given:

distance down the field in the first interval, $d_1=16\ m$

time duration of the first interval, $t_1=2.9\ s$

distance down the field in the second interval, $d_2=-2.5\ m$

time duration of the second interval, $t_2=1.65\ s$

distance down the field in the third interval, $d_3=24\ m$

time duration of the third interval, $t_3=5.2\ s$

velocity in the first interval:

$v_1=\frac{d_1}{t_1}$

$v_1=\frac{16}{2.9}$

$v_1=5.5172\ m.s^{-1}$

velocity in the second interval:

$v_2=\frac{d_2}{t_2}$

$v_2=\frac{-2.5}{1.65}$

$v_2=-1.5152\ m.s^{-1}$

velocity in the third interval:

$v_3=\frac{d_3}{t_3}$

$v_3=\frac{24}{5.2}$

$v_3=4.6154\ m.s^{-1}$

We know that the average velocity is given as the total displacement per unit time.

$v_{avg}=\frac{d_1+d_2+d_3}{t_1+t_2+t_3}$

$v_{avg}=\frac{16-2.5+24}{2.9+1.65+5.2}$

$v_{avg}=3.8462\ m.s^{-1}$

3 0

3 years ago

Defination of formula bar

Gekata [30.6K]

The Formula Bar is where data or formulas you enter into a worksheet appear for the active cell. The Formula Bar can also be used to edit data or formula in the active cell. The active cell displays the results of its formula while we see the formula itself in the Formula Bar.

mark me brainliestt :))

7 0

3 years ago

Read 2 more answers