Ammonia=a colorless gas with a characteristic pungent smell. It dissolves in water to give a strongly alkaline solution.
Inert=lacking the ability or strength to move.
Nitrates=a salt or ester of nitric acid, containing the anion NO3− or the group —NO3.
Limiting nutrient S=Nitrogen and phosphorus are frequently called “limiting nutrients.” This means that at any given time, one or the other of these nutrients may be the hardest nutrient for a plant to acquire and therefore be the only nutrient that is limiting the plant's growth.
saturation=the state or process that occurs when no more of something can be absorbed, combined with, or added. The degree or extent to which something is dissolved or absorbed compared with the maximum possible, usually expressed as a percentage.
Eutrophication=excessive richness of nutrients in a lake or other body of water, frequently due to runoff from the land, which causes a dense growth of plant life and death of animal life from lack of oxygen.
Nitrification=Nitrification is the biological oxidation of ammonia or ammonium to nitrite followed by the oxidation of the nitrite to nitrate. The transformation of ammonia to nitrite is usually the rate limiting step of nitrification. Nitrification is an important step in the nitrogen cycle in soil.
Denitrification=Medical Definition of denitrification. : the loss or removal of nitrogen or nitrogen compounds; specifically : reduction of nitrates or nitrites commonly by bacteria (as in soil) that usually results in the escape of nitrogen into the air.
Data:
wavelength (λ) = ?
wave speed (c) = 150 m/s
frequency (f) = 15 Hz (Hz = 1/s)
Formula
![\lambda = \frac{c}{f}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%20%5Cfrac%7Bc%7D%7Bf%7D%20)
Solving:
![\lambda = \frac{c}{f}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7Bc%7D%7Bf%7D%20)
![\lambda = \frac{150}{15}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B150%7D%7B15%7D%20)
![\boxed{\lambda= 10m}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Clambda%3D%2010m%7D)
Answer:
<span>
wavelength = 10 m</span>
Answer:
![3.037037037\times 10^{-16}\ C](https://tex.z-dn.net/?f=3.037037037%5Ctimes%2010%5E%7B-16%7D%5C%20C)
Explanation:
dr= Width = 30 μm
R = Radius = 1.8 cm
Q = ![2.05\times 10^6\times 1.6\times 10^{-19}](https://tex.z-dn.net/?f=2.05%5Ctimes%2010%5E6%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D)
r = 0.5 cm
Area is given by
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
Differentiating with respect to r
![dA=2\pi rdr](https://tex.z-dn.net/?f=dA%3D2%5Cpi%20rdr)
Surface charge density is given by
![\sigma=\dfrac{Q}{A}\\\Rightarrow \sigma=\dfrac{Q}{\pi r^2}](https://tex.z-dn.net/?f=%5Csigma%3D%5Cdfrac%7BQ%7D%7BA%7D%5C%5C%5CRightarrow%20%5Csigma%3D%5Cdfrac%7BQ%7D%7B%5Cpi%20r%5E2%7D)
Charge is given by
![q=\sigma dA\\\Rightarrow q=\dfrac{Q}{\pi r^2} 2\pi rdr\\\Rightarrow q=\dfrac{2Qrdr}{R^2}\\\Rightarrow q=\dfrac{2\times 2.05\times 10^6\times 1.6\times 10^{-19}\times 0.005\times 30\times 10^{-6}}{0.018^2}\\\Rightarrow q=3.037037037\times 10^{-16}\ C](https://tex.z-dn.net/?f=q%3D%5Csigma%20dA%5C%5C%5CRightarrow%20q%3D%5Cdfrac%7BQ%7D%7B%5Cpi%20r%5E2%7D%202%5Cpi%20rdr%5C%5C%5CRightarrow%20q%3D%5Cdfrac%7B2Qrdr%7D%7BR%5E2%7D%5C%5C%5CRightarrow%20q%3D%5Cdfrac%7B2%5Ctimes%202.05%5Ctimes%2010%5E6%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%200.005%5Ctimes%2030%5Ctimes%2010%5E%7B-6%7D%7D%7B0.018%5E2%7D%5C%5C%5CRightarrow%20q%3D3.037037037%5Ctimes%2010%5E%7B-16%7D%5C%20C)
The charge contained in the ring is ![3.037037037\times 10^{-16}\ C](https://tex.z-dn.net/?f=3.037037037%5Ctimes%2010%5E%7B-16%7D%5C%20C)
Answer:
4.56×10¯⁷¹ N
Explanation:
From the question given above, the following data were obtained:
Distance apart (r) = 1.10 m
Force (F) =?
NOTE:
Gravitational constant (G) = 6.67×10¯¹¹ Nm² /Kg²
Mass of electron = 9.1×10¯³¹ Kg
Mass of the two elections = M₁ = M₂ = 9.1×10¯³¹ Kg
Thus, we can obtain the force of attraction between the two elections as illustrated below:
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × (9.1×10¯³¹)² / (1.1)²
F = 4.56×10¯⁷¹ N
Thus, the force of attraction between the two elections is 4.56×10¯⁷¹ N
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
There should be an image that should accompanied your question, I was able to chcek it from other sources. the acceleration of the block when the scale reads 32N is <span>4.0 m/s*s</span>