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DENIUS [597]
2 years ago
11

A constant voltage of 3.00 V has been observed over a certain time interval across a 3.00 H inductor. The current through the in

ductor, measured as 3.00 A at the beginning of the time interval, was observed to increase at a constant rate to a value of 8.00 A at the end of the time interval. How long was this time interval?
Physics
1 answer:
frozen [14]2 years ago
5 0

Answer:

Explanation:

If L be inductance and i be current , flux associated with it

Φ = L i

emf induced = dΦ / dt = L di / dt

Putting the given values

emf induced = 3 V , L = 3 H

di = 8 - 3 = 5 A

dt = ?

3 = 3 x 5 / dt

dt or time duration = 3 x 5 / 3

= 5 sec .

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A 5.00-g bullet is fired into a 900-g block of wood suspended as a ballistic pendulum. The combined mass swings up to a height o
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Answer:

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Explanation:

From the question we are told that

   The mass  of the bullet is m_b  = 5.00 \ g  = 0.005 \  kg

  The mass  of the wood is  m_w =  900 \  g  =  0.90\  kg

   The height attained by the combined mass is  h =  8.0 \ cm  =  0.08 \ m

Generally according to the law of energy conservation    

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Here KE_b is the kinetic energy of the bullet before collision.

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