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aalyn [17]
3 years ago
8

A radioactive isotope has a half-life of 2.0 years. The fraction of a pure sample of the isotope

Chemistry
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer:

its a. 1/8

Explanation:

Arisa [49]3 years ago
3 0
Answer:

1/8

Explanation:

Uhm whatever the guy said ^ yeah hope you pass
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How many moles of SnF₂ will be produced along with 48 grams of H₂? *
KIM [24]

Answer: 24 moles of SnF_2 are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

{\text{Moles of}  H_2}=\frac{48g}{2g/mol}=24moles

Sn+2HF\rightarrow SnF_2+H_2

According to stoichiometry :

1 mole of H_2 is accompanied with = 1 mole of SnF_2

Thus 24 moles of H_2  is accompanied with =\frac{1}{1}\times 24=24moles  of SnF_2

Thus 24 moles of SnF_2 are produced.

8 0
3 years ago
Predict whether litmus paper will turn red or blue when dipped in:
Temka [501]

Answer:

a. blue, b. red, c. red, d. basic - blue

Explanation:

a.washing powder ( containing sodium carbonate ) basic -blue

b. orange juice ( containing citric acid )- acidic -red

c. lemonade ( containing H2CO₃ )-acidic - red

d. cleaner ( containg NH₃ )- basic - blue

7 0
3 years ago
During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

3 0
3 years ago
Can someone please explain the relationship between the group number, the number of valence electrons lost or gained, and the fo
soldi70 [24.7K]
<span>Ca has 2 valence electrons and F has 7, they would end up having to share electrons but Ca or F has to keep one because in total there are 9 valence elections and only 8 are needed to make this pair "happy". that's all i can provide. i hope it helped some</span>
6 0
3 years ago
Define law of conservation of mass
horrorfan [7]

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction. Hope this helps!


7 0
3 years ago
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