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anyanavicka [17]
3 years ago
5

A general change, such as increasing or decreasing numbers

Chemistry
1 answer:
Blababa [14]3 years ago
7 0

c)pattern

Explanation:

A general change such as increasing or decreasing numbers is called a pattern. A pattern shows a structured way of implementing a change.

  • Patterns can be a form of increment in values by adding a particular number at intervals.
  • It can be a division, multiplication or subtraction of a consistent number.
  • Patterns can provide insight into understanding a number system or a group of numbers.  
  • Sequences are usually derived from patterns.

Learn more:

Patterns brainly.com/question/4694425

#learnwithBrainly

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BartSMP [9]

Answer: 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

Explanation:

The balanced chemical reaction is :

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

According to stoichiometry :

2 moles of NH_3 give = 1 mole of (NH_4)_2SO_4

Thus 30.0 moles of NH_3 will give =\frac{1}{2}\times 30.0=15.0moles  of (NH_4)_2SO_4

Thus 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

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dusya [7]
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Look at the questions below and decide which is declarative.
Yuliya22 [10]
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3 years ago
A rigid tank that contains 2 kg of N2 at 25°C and 550 kPa is connected to another rigid tank that contains 4 kg of O2 at 25°C an
koban [17]

Answer:

The volume in the first tank = 0.32 m^{3}

The volume in the second tank = 2.066 m^{3}

The  final pressure of the mixture = 203.64 K pa

Explanation:

<u>First Tank </u>

Mass = 2 kg

Pressure = 550 k pa

Temperature = 25 °c = 298 K

Gas constant for nitrogen = 0.297 \frac{KJ}{Kg K}

From the ideal gas equation

P V = m R T

550 × V = 2 × 0.297 × 298

V = 0.32 m^{3}

This is the volume in the first tank.

<u>Second tank</u>

Mass =  4 kg

Pressure = 150 K pa

Temperature = 25 °c = 298 K

Gas constant for oxygen = 0.26  \frac{KJ}{Kg K}

From the ideal gas equation

P V = m R T

150 × V = 4 × 0.26 × 298

V = 2.066 m^{3}

This is the volume in the second tank.

This is the iso thermal mixing. i.e.

P_{3} V_{3}  = P_{1} V_{1} + P_{2} V_{2} ----- (1)

V_{3}  = V_{1}  + V_{2}

V_{3}  = 0.32 + 2.066

V_{3}  = 2.386 \ m^{3}

Put this value in equation (1)

P_{3} × 2.386 =  550 × 0.32 + 150 × 2.066

P_{3} = 203.64 K pa

Therefore the  final pressure of the mixture = 203.64 K pa

3 0
3 years ago
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