Answer:
Y = 62.5%
Explanation:
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In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:
Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:
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Answer:
-12.5 kJ/mol
Explanation:
The free-energy predicts if a reaction is spontaneous or not. If it is, ΔG < 0. When a reaction happens by steps, the free-energy of the global reaction can be calculated by the sum of the free-energy of the steps (Hess law). If it's needed to operations at the reaction the same operation must be done in the value of ΔG (if the reaction is inverted, the signal of ΔG must be inverted).
Phosphocreatine → creatine + Pi ∆G'° = –43.0 kJ/mol
ATP → ADP + Pi ∆G'° = –30.5 kJ/mol (x-1)
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Phosphocreatine → creatine + Pi ∆G'° = –43.0 kJ/mol
Pi + ADP → ATP ∆G'° = 30.5 kJ/mol
The bold compounds are in opposite sides, so they'll be canceled in the sum of the reactions:
Phosphocreatine + ADP → creatine + ATP
∆G'° = -43.0 + 30.5
∆G'° = -12.5 kJ/mol
Energy levels are considered orbitals.
Answer:
Generally, we know that ionic compounds are formed by reaction of metals and non metals and non metals form a covalent or non ionic bonds.
<u>IONIC COMPOUDS</u>
- Iron and chlorine (FeCl2) , ( FeCl3)
- Chlorine and Lithium (LiCl)
- oxygen and calcium ( CaO)
- Potassium and Sulphur ( K2S)
<u>NON IONIC COMPOUNDS</u>
- Potassium and Calcium (covalent bond)
- Sulphur and Bromine (covalent bond)
Explanation:
The nucleus of an atom of the element is positively charged and atom has a hollow space inside it.
Explanation:
This experiment was conducted by Rutherford in this experiment. He placed a gold foil and surround it with a screen.
And He exposed gold foil in alpha particles rays in which he noticed that most rays passed through atom which conclude that atom has a large space, some rays get deflected and some reverse their path this show that the positive charge of nucleus of an atom.
