Question

What volume of H2O(g) is produced when 8.00 mol of C2H4(g) reacts at STP?

Answer 1

* Mole ratio:

C2H4 + 3 O2= 2 CO2 + 2 H2O

1 mole C2H4 --------------- 2 moles H2O
8.00 moles C2H4 ---------- ?

8.00 x 2 / 1 => 16 moles of H2O

Therefore:

1 mole --------- 22.4 L at ( STP)
16 moles ------- ?

16 x 22.4 / 1 => 358.4 L

hope this helps!