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Lunna [17]
3 years ago
8

#1 What materials is each part of the flashlight made of? (A flashlight will include wires,a light bulb,a lens, a reflector ,and

an exterior casing.) #2 For each part,why was that material chosen? #3 For each part,would material have worked as well?
Physics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

Explanation:

Question 1

1.The wires are made of conducting materials e.g copper

2. A light bulb is made of filament material e.g tungsten with gases enclosed in a glass material

3.The lens is made of transparent glass material

4 The reflector is made of plastic with silver lining

5. The exterior casing of most flash lights are made of plastic

Question 2.

1.Copper is used to conduct electric current from the battery to the bulb

2.The tungsten filament ignite the gases and causes it to glow

3. The lens covers the lamp on your flashlight so that the glass on the lamp

/bulbs does not get broken.

4.The reflector redirects the light rays from the lamp, creating a steady beam of light, which is the light you see emitting from the flashlight.

5. The exterior cases houses the entire assembly and makes the flash light handy for use

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Explanation:

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3 years ago
a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
enyata [817]

Answer: Escaped volume = 0.0612m^3

Explanation:

According to Boyle's law

P1V1 = P2V2

P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

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3 years ago
A flat sheet of paper of area 0.365 m2 is oriented so that the normal to the sheet is at an angle of 60 ∘ to a uniform electric
andriy [413]

Answer:

A.) 3.65 N*m²/C B) No C) 0º D) 90º

Explanation:

A) The electric flux, when the electric field is uniform across a gausssian surface, can be calculated as the dot product of the electric field vector, and the vector representing the area of the surface (normal to the surface and directed outward it by convention), as follows:

Flux = E*A*cos φ

where E = 20 N/C, A = 0.365 m², φ = 60º.

Replacing by the values, we can get the value of the electric flux, as follows:

Flux = 20 N/C* 0.365 m²*0.5 = 3.65 N*m²/C

B) While the area remains constant, and doesn't change orientation, the value of the flux will be the same, regardless the shape of the sheet.

C) When the normal to the sheet and the electric field are parallel each other, the surface will intercept the maximum number of field lines, i.e. the flux will be directly E*A*cos 0º = E*A (maximum value possible).

D) When the electric field is tangent to the surface, this means that no field lines will be intercepted by the sheet, so the flux is zero.

In this case, φ = 90º, cos φ = 0

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Answer:

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The median is found by listing the numbers in order numerically and finding the one that is right in the middle. In this case you have 1, 3, 5, 6, 7, 12, 15 where the middle term is 6.

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