Answer:
Force on the singly charged ion will be
Explanation:
We have given electric field E = 8 MN/C
So electric field in N/C will be
It is given that ion so charge on ion will be equal to
We have to find the electric force on the ion
Electric force is equal to , here q is charge and E is electric field
So force on the charge will be equal to
So force on the singly charged ion will be
Answer:
Work done, W = 0 J
Explanation:
It is given that,
Weight of the bucket, W = F = 35 N
It is lifted vertically 3 m and then returned to its original position. We need to find the work gravity do on the bucket during this process.
Work done when the bucket is lifted vertically, W₁ = -mgh
Work done when the bucket returned to its original position, W₂ = +mgh
Net work done, W = W₁ + W₂
W = 0 J
So, the work done on the bucket is zero. Hence, this is the required solution.
<span>
Of course. Wind is air in motion, and the gases in air are composed of
all the usual familiar stuff ... atoms, molecules, mass, etc. That's how
the wind moves things ... it has momentum and kinetic energy, which
get transferred to the things that move in the wind.</span>
Answer:
ΔR = 9 s
Explanation:
To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value
The given expression is R = 2A / B
the uncertainty is ΔR = | | ΔA + | | ΔB
we look for the derivatives
= 9 / B
= 9A ( )
we substitute
ΔR = ΔA + ΔB
the values are
ΔA = 2 s
ΔB = 3 s
ΔR = 2 + 3
ΔR = 1.636 + 7.14
ΔR = 8,776 s
the absolute error must be given with a significant figure
ΔR = 9 s