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Radda [10]
3 years ago
7

The mass of a proton is approximately equal to

Physics
1 answer:
Dahasolnce [82]3 years ago
3 0

Answer:

1.6726\cdot 10^{-27} kg

Explanation:

The three main particles that make an atom are:

- Proton: its mass is 1.6726\cdot 10^{-27} kg, it carries an electric charge of +e (e=1.6\cdot 10^{-19}C), and it is located in the nucles of the atom

- Neutron: its mass is 1.6749 \cdot 10^{-27}kg, it carries no electric charge, and it is also located in the nucleus of the atom

- Electron: its mass is 9.1094 \cdot 10^{-31}kg, it carries an electric charge of -e (e=1.6\cdot 10^{-19}C), and it is located outside the nucleus

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Let's take two balls, each of radius 0.1 meters and charge them each to 3 microCoulombs. Then, let's put them on a flat surface
salantis [7]

Explanation:

First, we will calculate the electric potential energy of two charges at a distance R as follows.

                   R = 2r

                      = 2 \times 0.1 m

                      = 0.2 m

where,    R = separation between center's of both Q's. Hence, the potential energy will be calculated as follows.

                U = \frac{k \times Q \times Q}{R}

                    = \frac{8.98 \times 10^{9} \times (3 \times 10^{-6} C)^{2}}{0.1}

                    = 0.081 J

As, both the charges are coming towards each other with the same energy so there will occur equal sharing of electric potential energy between these two charges.

Therefore, when these charges touch each other then they used to posses maximum kinetic energy, that is, \frac{U}{2}.

Hence,   K.E = \frac{U}{2}

                     = \frac{0.081}{2}

                     = 0.0405 J

Now, we will calculate the speed of balls as follows.

                 V = \sqrt{\sqrt{\frac{2 \times K.E}{m}}

                     = \sqrt{\sqrt{\frac{2 \times 0.0405}{4 kg}}

                     = 0.142 m/s

Therefore, we can conclude that final speed of one of the balls is 0.142 m/s.

6 0
2 years ago
What does the law of conservation of energy state?
VikaD [51]

The total amount of energy remains constant in an isolated system. It implies that energy can neither be created nor destroyed, but can be change from one form to another.

6 0
3 years ago
1. When an object is at rest, not moving, and is crashed into by another
wlad13 [49]

Answer:

both experience forces or at least a force

Explanation:

it would go in the direction the other object

(second object, the one that crashed) was going

si if going right then right if left then left

plus or minus

4 0
3 years ago
A passenger plane is flying above the ground.Describe the two components of its mechanical enserfy
Goryan [66]
The force and the air resistance depends on the mechanical enserfy.
3 0
3 years ago
At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak
Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

P = AI

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

A = \frac{\pi d^2}{4}

Now the intensity is inversely proportional to the square of the distance from the source, then

I \propto \frac{1}{r^2}

The expression for the intensity at different distance is

\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}

Here,

I_1 = Intensity at distance 1

I_2 = Intensity at distance 2

r_1 = Distance 1 from light source

r_2 = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

I_2 = I_1 (\frac{r_1^2}{r_2^2})

If we replace with our values at this equation we have,

I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})

I_2 = 1.11*10^{-4} W/m^2

Now using the equation to find the area we have that

A = \frac{\pi (8.4*10^{-3}m)^2}{4}

A = 5.5*10^{-5}m^2

Finally with the intensity and the area we can find the sound power, which is

P = AI

P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)

P = 6.1*10^{-9}J/s

Power is defined as the quantity of Energy per second, then

E = 6.1*10^{-9}J

8 0
3 years ago
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