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tekilochka [14]

2 years ago

9

What is this a solid, liquid, or a gas, "The particles that are locked in fixed positions"

1 answer:

katovenus [111]2 years ago

7 0

States of matter are determined by temperature. When the temperature is more cold, the particles move less. The colder the temperature, the more solid something becomes. Because the particles are in fixed positions, they do not move much, they are colder, and they are solid. Also, you cannot pass your hand through locked atoms. If you swipe your hand through water or gas, it parts. Solids, however, are fixed and cannot be passed by without significant force to break it.

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Which catalyzed reaction breaks up ozone? 2H2O2(l) right arrow with upper M n upper O subscript 2 above it. 2H2O(l) + O2 O3 + O

anyanavicka [17]

Answer: B

Explanation: The answer is B

6 0

3 years ago

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How many ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

olganol [36]

Answer: 127.5ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HNO_3$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.75M\\V_2=85mL$

Putting values in above equation, we get:

$1\times 0.5\times V_1=1\times 0.75\times 85\\\\V_1=127.5mL$

Thus 127.5 ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

6 0

3 years ago

How many charges do copper(II) and Carbide have

MAVERICK [17]

Answer:

Copper is 2+ and carbide is 2-

5 0

3 years ago

If you drive at 100 km/hr for 6 hours how far will you go

Sergeu [11.5K]

Answer:

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Explanation:

Have a good day :)

7 0

2 years ago

Read 2 more answers

A chromium oxide compound contains 104.0 grams of chromium and 48.0 grams of oxygen. What is the most likely empirical formula o

TEA [102]

Answer: Empirical formula of this compound is $Cr_2O_3$

Explanation:

Mass of Cr= 104.0 g

Mass of O = 48.0 g

Step 1 : convert given masses into moles.

Moles of Cr = $\frac{\text{ given mass of Cr}}{\text{ molar mass of Cr}}= \frac{104.0g}{52g/mole}=2moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.0g}{16g/mole}=3moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Cr = $\frac{2}{2}=1$

For O = $\frac{3}{2}=1.5$

Converting into simple whole number ratios by multiplying by 2

The ratio of Cr : O= 2: 3

Hence the empirical formula is $Cr_2O_3$

The most likely empirical formula of this compound is $Cr_2O_3$

4 0

3 years ago