3 years ago

When hydrogen reacts with oxygen, hydrogen loses electrons. Which term

Physics

2 answers:

Tanya [424]3 years ago

4 0

Answer: Correct answer is A

Explanation: Ap3x appointment

Inga [223]3 years ago

3 0

Answer:

A.) Oxidation

Explanation:

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Find the value of the spring constant for the spring in Trial I. Use 0.367 s for the value of the period. The mass of the suspen

Agata [3.3K]

Answer:

117.28 N/m

Explanation:

step one:

given

Period T= 0.367s

mass m= 0.4kg

Required

the spring constant k

Step two:

The expression for the period, mass and spring constant relation is

T=2π√m/k

making k subject of the formula

$T/2 \pi = \sqrt m/k$

square both sides

$(T/2 \pi)^2= m/k$

$k= m/(T/2 \pi)^2$

$k=0.4/(0.367/2*3.142)^2$

$k=0.4/(0.05840)^2$

$k=0.4/0.0034105\\\\k=117.28 N/m$

8 0

3 years ago

A simple pendulum has a period of 2.5 s. What is its period if its length is increased by a factor of four?

Svetach [21]

Answer:

Its period if its length is increased by a factor of four is 5 s.

Explanation:

The period of a simple pendulum is given by;

$T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi} = \sqrt{\frac{l}{g} } \\\\ \frac{T^2}{4\pi^2} = \frac{l}{g}\\\\\frac{T^2}{l} = \frac{4\pi^2}{g} \\\\let \ \frac{4\pi^2}{g} \ be \ constant \\\\\frac{T_1^2}{l_1} = \frac{T_2^2}{l_2} \\\\$

Given;

initial period, T₁ = 2.5

initial length, = L₁

new length, L₂ = 4L₁

the new period, T₂ = ?

$\frac{T_1^2}{l_1} = \frac{T_2^2}{l_2} \\\\T_2^2 = \frac{T_1^2 l_2}{l_1} \\\\T_2 = \sqrt{\frac{T_1^2 l_2}{l_1}} \\\\ T_2 = \sqrt{\frac{(2.5)^2 \ \times \ 4l_1}{l_1}}\\\\ T_2 =\sqrt{(2.5)^2 \ \times \ 4}\\\\T_2 = \sqrt{25} \\\\T_2 = 5\ s$