For question 1 if you have your acceleration equal to -9.8m/s^2 then you can find how fast it is traveling when it hits the water. You would use the equation Vf=Vi+a(t). You are looking for your Vf. Vi is 0m/s. a is -9.8m/s^2. t is 3.87s. If you now plug in what you have and solve you would end up with Vf=-37.926. For how far did it drop use the equation, d=Vi(t)+1/2(a)(t)^2. plug in the Vi, a, and t and solve. Then you are left with the distance vertically being 73.38681m (don't forget sig figs). (When you solve for d it ends up being negative, but because you can't ever go backwards in distance it has to be positive)
Answer:
adapted from NOVA, a team of historians, engineers, and trade experts recreate a medieval throwing machine called a trebuchet. To launch a projectile, a trebuchet utilizes the transfer of gravitational potential energy into kinetic energy. A massive counterweight at one end of a lever falls because of gravity, causing the other end of the lever to rise and release a projectile from a sling. As part of their design process, the engineers use models to help evaluate how well their designs will work.
Explanation:
Answer:
291.598 N-m
291.6 N-m
Explanation:
Let's first take a look at the free bodily diagrammatic representation.
The first diagram will aid us in answering question (a), so as the second diagram will facilitate effective understanding when solving for question (b).
Let's first determine our angle θ from the diagram
To find angle θ ; we have :
tan θ =
tan θ =
tan θ = 1.333
θ = tan⁻¹ (1.333)
θ = 53.13°
Now, to determine the moment about B of the force exerted by the cord at point A by resolving that force into horizontal and vertical components applied at point A.
We have:
where Force(F) = Force in the cord AC = 1350 N and θ = 53.13° ; we have:
Since the negative sign illustrates just the clockwise movement ; then the moment about B of the force exerted by the cord at point A by resolving that force into horizontal and vertical components applied at point A = 291.598 N-m
b) From the second diagram, taking the moment at point B ,
we have:
where Force(F) = 1350 N and θ = 53.13° ; we have:
Since the negative sign illustrates just the clockwise movement ; then the moment about B of the force exerted by the cord at point A by resolving that force into horizontal and vertical components applied at point C = 291.6 N-m
Answer:
1.986 * 100,000 = 1,986,000
Answer:
Gravitation
Explanation:
Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects.