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Anon25 [30]
3 years ago
5

What does it mean by the fact that the acceleration of a car is 5m/s square??​

Physics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

An acceleration of 5m/s^2 means that the velocity of a body is increasing by 5m/s per second in a certain direction

Explanation:

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Explanation:

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Calculate the average times it took the car to travel 0. 25 and 0. 50 meters. Record the averages, to two decimal places, in Tab
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The average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.

<h3>How to calculate the Average speed?</h3>

The average speed can be calculated by adding the speed of each trial divided by the number of trials,

For 0.25 m the average speed will be:

S_{avg} = \dfrac{2.24 + 2.21 + 2.23}{ 3}\\\\S_{avg} = 2.22

For the 0.50 m, the average speed will:

S_{avg} = \dfrac {3.16 + 3.08 + 3.15} {3 }\\\\S_{avg}  = 3.13\rm \  s

Therefore, the average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.

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2 years ago
How would the force of gravity between two objects change if the mass of
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Answer:

Option C. The force between them would be 4 times larger than with the

initial masses.

Explanation:

To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:

From:

F = GMₐM₆/ r²

Keeping G/r² constant, we have

F₁ = MₐM₆

Let the initial mass of both objects to be m

F₁ = MₐM₆

F₁ = m × m

F₁ = m²

Next, let the masses of both objects doubles i.e 2m

F₂ = MₐM₆

F₂ = 2m × 2m

F₂ = 4m²

Compare the initial and final force

Initial force (F₁) = m²

Final (F₂) = 4m²

F₂ / F₁ = 4m² / m²

F₂ / F₁ = 4

F₂ = 4F₁ = 4m²

From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the

initial masses.

Thus, option C gives the correct answer to the question.

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