A car drives 16 miles south and then 12 miles west. What is the magnitude of the car’s displacement?

You are designing a solenoid to produce a 2.0-kG magnetic field. You wish to wrap your insulated wire uniformly around a cardboa

Sloan [31]

Answer:

92.7 km

Explanation:

Since the magnetic field due to a solenoid is given by B = μ₀Ni/L where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid, L = length of cardboard tube = 58 cm = 0.58 m, , i = current in wire = 2.5 A and l = length of wire.

So, N = BL/μ₀i

Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T

So, substituting the variables into the equation, we have

N = BL/μ₀i

N = 0.2 T × 0.58 m/(4π × 10⁻⁷ H/m × 2.5 A)

N = 1.16 Tm/(31.416 × 10⁻⁷ HA/m)

N = 0.0369 × 10⁷ turns

N = 3.69 × 10⁵ turns

length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m

So, l = NC

= NπD

= πND

= π × 3.69 × 10⁵ turns × 0.08 m

= 0.9274 × 10⁵ m = 9.274 × 10⁴ m

= 92.74 × 10³ m

= 92.74 km

≅ 92.7 km

5 0

2 years ago

You attach a 3.10 kg weight to a horizontal spring that is fixed at one end. You pull the weight until the spring is stretched b

dolphi86 [110]

Answer:

0.785 m/s

Explanation:

Hi!

To solve this problem we will use the equation of motion of the harmonic oscillator, i.e.

$x(t) = A cos(\omega t )+B sin(\omega t)$ - (1)

$\frac{dx}{dt}(t) = \omega (B cos(\omega t )- A sin(\omega t)$ - (1)

The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:

$x(0) = 0.100$

$\frac{dx}{dt}(0) = 0$

Since cos(0)=1 and sin(0) = 0:

$x(0)=A$

$\frac{dx}{dt}(0) = -B\omega$

We get

$A =0.100\\B = 0$

Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:

$x(0.4) = - 0.100$

Since

$x(t) = 0.100 cos(\omega t)\\ -0.100=x(0.4)=0.100cos(\omega 0.4)$

This is the same as:

$-1 = cos(0.4\omega)$

We know that cosine equals to -1 when its argument is equal to:

(2n+1)π

With n an integer

The first time should happen when n=0

Therefore:

π = 0.4ω

or

ω = π/0.4 -- (2)

Now, the maximum speed will be reached when the potential energy is zero, i.e. when the sping is not stretched, that is when x = 0

With this info we will know at what time it happens:

$0 = x(t) = 0.100cos(\omega t)$

The first time that the cosine is equal to zero is when its argument is equal to π/2

i.e.

$t_{maxV}=\pi /(2\omega)$

And the velocity at that time is:

$\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\omega t_{maxV})\\\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\pi/2)\\$

But sin(π/2) = 1.

Therefore, using eq(2):

$\frac{dx}{dt}(t_{maxV} ) = 0.100*\omega = 0.100\frac{\pi}{0.400} = \pi/4$

And so:

$V_{max} = \pi / 4 =0.785$

6 0

2 years ago

Carly rode her bike for 300 meters in 30 seconds. One can calculate her

Nutka1998 [239]

Answer:

10

Explanation:

300 ÷ 30 = 10

Answer - 10

Hope this helps!!!

5 0

2 years ago

hii, just wondering how to solve this? it’s simple scientific notation but my brain just isn’t functioning today so it’s be help

arlik [135]

Honestly just use desmos or mathyway

8 0

2 years ago

5) A person holds a 1.7 kg bucket and lets it move down at

Elena L [17]

Answer:

12.5J

Explanation:

Given parameters:

Mass of bucket = 1.7kg

Height = 75cm = 0.75m

Unknown;

Work done on the bucket by the person = ?

Solution:

To solve this problem, we use the work done equation;

Work done = force x distance = mgh

m is the mass

g is the acceleration due to gravity

h is the height

Now, insert parameters and solve ;

Work done = 1.7 x 9.8 x 0.75 = 12.5J

7 0

2 years ago