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Katarina [22]
4 years ago
7

Where is the resistor located on the diagram?

Physics
2 answers:
Blababa [14]4 years ago
7 0

The answer is B.  O-O


Hope this helps

Please mark as Brainliest(:

Andrej [43]4 years ago
5 0
The answer is B hope this helps
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17. ____ Objects with more mass have
AnnZ [28]

a. more gravity

This is the answer.

5 0
3 years ago
"if the left-hand mass is 2.3 kg ,what should the right-hand mass be so that it accelerates downslope at 0.64 m/s2?"
VARVARA [1.3K]

m₁ = 2.3 kg <span>
θ₁ = 70° </span><span>
θ₂ = 17° </span><span>
g = 9.8 m/s² 

->The component of the gravitational force on m₁ that is parallel down the incline is: </span><span>
F₁ = m₁ × g × sin(θ₁) </span><span>
F₁ = (2.3 kg) × (9.8 m/s²) × sin(70°) = 21.18 N </span><span>

->The component of the gravitational force on m₂ that is parallel down the incline is: </span><span>
F₂ = m₂ × g × sin(θ₂) </span><span>
F₂ = m₂ × (9.8 m/s²) × sin(70°) = m₂ × (2.86 m/s²) </span><span>

Then the total mass of the system is: 
m = m₁ + m₂ </span><span>
m = (2.3 kg) + m₂ </span><span>

If it is given that m₂ slides down the incline, then F₂ must be bigger than F₁, </span><span>
and so the net force on the system must be: 
F = m₂×(2.86 m/s²) - (21.18 N) </span><span>

Using Newton's second law, we know that 
F = m × a 
So if we want the acceleration to be 0.64 m/s², then 
m₂×(2.86 m/s²) - (21.18 N) = [(2.3 kg) + m₂] × (0.64 m/s²) </span><span>
m₂×(2.86 m/s²) - (21.18 N) = (1.47 N) + m₂×(0.64 m/s²) </span><span>
m₂×(2.22 m/s²) = (22.65 N) </span><span>
m₂<span> = 10.2 kg</span></span>

5 0
4 years ago
A source emits sound uniformly in all directions. There are no reflections of the sound. At a distance of 12 m from the source,
yaroslaw [1]

Answer:

1.58 W

Explanation:

Since the sound spreads uniformly in all directions, it must be in a form of a circle with radius of 12 m. So the area of the circle is

A = \pi r^2 = \pi 12^2 = 452.389 m^2

From the intensity of the sound we can calculate the power at 12 m

P = AI = 452.389 * 3.5\times10^{-3} = 1.58 W

7 0
3 years ago
A bullet with a mass ????b=13.5 g is fired into a block of wood at velocity ????b=249. The block is attached to a spring that ha
larisa86 [58]

Answer:

M = 0.436 kg

Explanation:

As per energy conservation we can say that energy stored in the spring at the position of maximum compression must be equal to the kinetic energy of bullet and block system

so here we have

\frac{1}{2}(m + M)v^2 = \frac{1}{2} kx^2

here we know that

k = 205 N/m

x = 35 cm

\frac{1}{2}(m + M)v^2 = \frac{1}{2}(205)(0.35)^2

now by momentum conservation we know that

mv_o = (m + M)v

v = \frac{m}{m + M} v_o

now plug in all values in it

v = \frac{0.0135}{0.0135 + M}(249)

now from above equation

\frac{1}{2}(0.0135 + M)( \frac{0.0135}{0.0135 + M}(249))^2 = 12.56

\frac{5.65}{0.0135 + M} = 12.56

by solving above equation we have

M = 0.436 kg

3 0
4 years ago
Suppose that 100g of aluminum at 23 degrees C is added to 50g of water at 95 degrees C. Determine the equilibrium temperature of
blagie [28]
Heat capacities of both the substances be given in such situations
5 0
3 years ago
Read 2 more answers
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