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Arlecino [84]
4 years ago
15

DETERMINE THE LAUNCH ELEVATION AND MAXIMUM RANGE: The test vehicle should obtain a burnout velocity of 7200 m/s at 180 km altitu

de (RBurnout = 6558 km). What would the flight path angle (fBurnout) be?
Physics
1 answer:
fenix001 [56]4 years ago
8 0

Answer:

Flight path angle= 15.12°, maximum range= 5.29× 10*6 km

Explanation:

u= 7200m/s, H= 180km= 180000m

Recall that

Maximum height, H= (u*2sin*2∆)/2g

180000= (7200×7200sin*2∆)/2×9.8

(18000×2×98)/7200×7200= sin*2∆

Sin∆= 0.2609

∆= 15.12°

Maximum range, R= u*2/g

(7200×7200)/9.8

= 5289795.92km

= 5.29× 10*6 km

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If two identical cars are traveling at different velocities, which car has the greatest momentum ​
vodomira [7]

Answer:

The one with highest velocity

Explanation:

The momentum of an object is given by

p=mv

where

m is the mass of the car

v is the velocity of the car

In this problem, we have two identical cars: identical means they have same mass, so

m_1 = m_2 = m

The momentum of car 1 is

p_1 = mv_1

while the momentum of car 2 is

p_2 = mv_2

By comparing the two expressions, we see that the car with greatest momentum is the one with highest velocity, since the mass is the same.

8 0
3 years ago
You go rock climbing with a pack that ways 79 N and you reach a height of 30 m. How much work did you do to lift your pack? If y
Vanyuwa [196]
When you climb, earth exerts gravitational force on pack in downward direction(pointing towards the center of earth).
In order to climb, you need to work against work done by gravity on the pack.
Hence work done by you = work done by gravity on pack 
                                        = Force x displacement = 70 x 30 = 2100 J.
 
4 0
3 years ago
1. Newton's 3rd Law states...
Vika [28.1K]

Answer:

C

Explanation:

There's a reason newton's 3rd law is called action-reaction :D

A - 1st law/inertia

B - 2nd law/f=ma

5 0
3 years ago
An infinite plane of charge has surface charge density 7.2 μC/m^2. How far apart are the equipotential surfaces whose potential
Rina8888 [55]

Answer:

so the distance between two points are

d = 0.246 \times 10^{-3} m

Explanation:

Surface charge density of the charged plane is given as

\sigma = 7.2 \mu C/m^2

now we have electric field due to charged planed is given as

E = \frac{\sigma}{2\epsilon_0}

now we have

E = \frac{7.2 \times 10^{-6}}{2(8.85 \times 10^{-12})}

E = 4.07 \times 10^5 N/C

now for the potential difference of 100 Volts we can have the relation as

E.d = \Delta V

4.07 \times 10^5 (d) = 100

d = \frac{100}{4.07 \times 10^5}

d = 0.246 \times 10^{-3} m

3 0
3 years ago
If an astronaut travels to different planets, which of the following planets will the astronaut’s weight be the same as on Earth
Nataly_w [17]
<h2>Astronaut travels to different planets - Option 4 </h2>

If an astronaut travels to different planets, none of the planets will the astronaut’s weight be the same as on Earth. On jupiter, weight will be more than the weight on earth. For instance if an astronaut has 100kg on earth then he will have 252 kg on jupiter.

On Mars, weight will be less than the weight on the earth. For instance, if an astronaut has 68 kg on earth then he will has 26 kg on mars. On Mercury, weight of an astronaut will be less than the weight on earth. Example if he has 68 kg on earth then he will have 25.7kg on mercury.

Hence, none of these planets the weight of astronaut will be same as on earth.

3 0
4 years ago
Read 2 more answers
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