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Arlecino [84]
3 years ago
15

DETERMINE THE LAUNCH ELEVATION AND MAXIMUM RANGE: The test vehicle should obtain a burnout velocity of 7200 m/s at 180 km altitu

de (RBurnout = 6558 km). What would the flight path angle (fBurnout) be?
Physics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

Flight path angle= 15.12°, maximum range= 5.29× 10*6 km

Explanation:

u= 7200m/s, H= 180km= 180000m

Recall that

Maximum height, H= (u*2sin*2∆)/2g

180000= (7200×7200sin*2∆)/2×9.8

(18000×2×98)/7200×7200= sin*2∆

Sin∆= 0.2609

∆= 15.12°

Maximum range, R= u*2/g

(7200×7200)/9.8

= 5289795.92km

= 5.29× 10*6 km

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As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh
marshall27 [118]

Answer:

The resultant velocity is  v_t=10 knots

Explanation:

Apply the law of conservation of momentum

     M_L *v_L + M_f * V_f = (M_L + M_f) v_t

Where M_L is the mass of the Luxury Liner = 40,000 ton

            v_L is the velocity of Luxury Liner = 20 knots due west

            M_f mass of freighter = 60,000

           v_f is the velocity of freighter = 10 knots due north

Apply the law of conservation of momentum toward the the west direction

         v_f = 0 \ knots

So the equation would be

              M_L *v_L = (M_L + M_f) v_t

Substituting values

            40000*20 = (40000+ 60000)v_t_w

Where v_t_w the final velocity due west

Making v_t_w the subject

          v_t_w = \frac{40,000* 20}{(40000 + 60000)}

                = 8 \ knots

Apply the law of conservation of momentum toward the the north direction          

          v_L = 0 \ knots

So the equation would be

           M_f *v_f = (M_L + M_f) v_t_n

Where v_t_n the final velocity due north

     Making v_t_n the subject

          v_t_n = \frac{60,000* 10}{(40000 + 60000)}

                = 6 \ knots

The resultant velocity is

       v_t = \sqrt{v_t_w^2 + v_t_n^2}

            = \sqrt{8^2 +6^2}

           v_t=10 knots

8 0
3 years ago
Which one is having lesser ressistance. a 60w bulb or a 40w bulb?
Ivan
Power dissipation = (voltage across the component)² / (resistance of the component)

Since the resistance is in the denominator of the fraction in this formula for the
quantity of power dissipated, you can see that when the supply voltage is constant,
the smaller resistance dissipates more power.

So the <u>60w bulb</u> has lower resistance than the 40w bulb.
8 0
3 years ago
What is the definition for the word energy?​
Lena [83]
Kinetic, thermal and electrical. There is more then one form of energy
4 0
3 years ago
A baseball player slides into third base with an initial speed of 4.0 m/s. If the coefficient of
musickatia [10]
The frictional force is given by F = μmg 

<span>where μ is the coeficient of friction. </span>

<span>Work done by frictional force = Fd = μmgd </span>

<span>Kinetic energy "lost" = 1/2 mv² </span>


<span>Fd = μmgd = 1/2 mv² </span>

<span>The m's cancel μgd = v² / 2 </span>



<span>d = v² / 2μg </span>

<span>d = 8² / 2(0.41)(9.8) </span>

<span>d = 32 / (0.41)(9.8) </span>

<span>d = 7.96 </span>

<span>Player slides 8 m . </span>



<span>Note. In your other example μ = 0.46 and v = 4 m/s </span>



<span>d = v² / 2μg </span>




<span>= 4² / 2(0.46)(9.8) </span>

<span>= 8 / (0.46)(9.8) </span>

<span>= 1.77 or 1.8 m.
</span>
Hope i Helped :D
3 0
4 years ago
Read 2 more answers
A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 P
MArishka [77]

Answer:

F \approx 19.5 N

Explanation:

From the question we are told that:

Pressure of  P_{CO_2}=1.50 * 105 Pa.

Bottle cap area A_b= 4.40 * 10-4 m^2

 

Generally the equation for Resultant pressure P_r is give as is mathematically given by

P_r=P_{CO_2}-P_a

Where

P_a=atmospheric\ pressure = 1.013*10^5 pa

P_r=1.50 * 105 Pa-1.013*10^5 pa

P_r=0.487*10^5 pa

Generally the equation for Force exerted by screw F is give as is mathematically given by

F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N

F \approx 19.5 N

4 0
2 years ago
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