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3 years ago

Read the paragraph below from the section "An Object At Rest Has Potential Energy

Physics

1 answer:

ch4aika [34]3 years ago

8 0

I think it’s d because it talks about a spring with is common like the spring in a pen

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Which two formulas are used to calculate potential and kinetic energy

goblinko [34]

Answer:

gravitational potential energy:

GPE = m g h

kinetic energy:

KE = 1/2 m v^2

6 0

3 years ago

Read 2 more answers

A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?

Yanka [14]

Answer:

$\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}$

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

$\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}$

Substituting values of m & v in the equation:

$\sf \implies KE = \frac{1}{2} \times 380.2 \times {11}^{2}$

$\sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 190.1 \times 121$

$\sf \implies KE = 190.1 \times 121$

$\sf \implies KE = 23002.1 \: J$

$\therefore$

Kinetic energy of the polar bear (KE) = 23002.1 J

5 0

3 years ago

You stand on top a building 44 m tall with a water balloon. You drop the water balloon from rest. How fast is the balloon moving

BabaBlast [244]

Y₀ = initial position of the balloon at the top of the building = 44 m

Y = final position of the balloon at halfway down the building = 44/2 = 22 m

a = acceleration of the balloon = - 9.8 m/s²

v₀ = initial velocity of the balloon = 0 m/s

v = final velocity of the balloon = ?

using the kinematics equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

v² = 0² + 2 (- 9.8) (22 - 44)

v = 20.78 m/s

4 0

3 years ago

An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the

bonufazy [111]

The upward force is 737 N

6 0

3 years ago

An electron and a proton are fixed at a separation distance of 973 nm. Find the magnitude and the direction of the electric fiel

Vilka [71]

Answer:

The magnitude is: $|E|=6084.1\: N/C$

The direction of E is in the negative x-direction.

Explanation:

The electric field equation is:

$E=k\frac{Q}{r^{2}}$

Where:

Q is the charge (we can choose the electron or the proton)
r is the distance (in our case is at the midpoint 973/2 nm)
k is the Coulomb constant ( $9*10^{9}\: Nm^{2}C^{-2}$ )

Using the electron charge ( $e = -1.6*10^{-19}\: C$ )

$E=-9*10^{9}\frac{1.6*10^{-19}}{(486.5*10^{-9})^{2}}$

The magnitude is:

$|E|=6084.1\: N/C$

The direction of E is in the negative x-direction.

I hope it helps you!

6 0

2 years ago